Part II: Assuming a p-value cut-off of 0.05, what is the critical value for this test? Enter your answer to three decimal places (e.g., 8.888).
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- In pre-DNA fingerprint days, blood type was often used in paternity disputes to exclude possible fathers. If the man in question has type B blood, and the child has type A blood, and the mother has type AB blood, can the man be the father of the child? Group of answer choices Yes, but only if he is homozygous for the B allele No Yes, but only if he is heterozygous for the B allele Yes, but only if both of his parents were Type ABThis is a modified question from the textbook, Campbell Biology in Focus (3rd edition), question #5 on page 256. A man with normal vision marries a woman with normal vision whose father was red-green color-blind (a recessive, sex-linked condition). Assuming that the woman's mother had normal vision and did not carry the recessive gene, what is the probability that the married couple will have a color-blind daughter? That their first son will be color-blind? That their second son will be color-blind? Include Punnett square for each question in your answer. You may find the below diagram helpful (the orange square means the individual has the phenotype of color-blindness, while the beige means the individual is a carrier of the mutated color-blind gene where XN and Xn represent dominant and recessive allele, respectively).Which of the following rows correctly identifies the relationship between the blood type alleles IA, IB, and i? Select one: a. Relationship between IA and IB Relationship between IB and i Incomplete dominance Codominance b. Relationship between IA and IB Relationship between IB and i Multiple alleles Incomplete dominance c. Relationship between IA and IB Relationship between IB and i Dominant and recessive Multiple alleles d. Relationship between IA and IB Relationship between IB and i Codominance Dominant and recessive
- In a species of dog, a mutant gene that causes deafness is found on the Y chromosome. What type of offspring will be produced between a cross of male dog whose father is deaf, and female dog whose father is not deaf? Question 16 options: 25% normal female dogs, 25 % deaf female dogs, 25 % normal male dogs, 25 % deaf male dogs 50% normal female dogs, 50 % deaf male dogs 50% deaf female dogs, 50 % deaf male dogs 50% normal female dogs, 25 % deaf male dogs, 25% normal male dogsPlease answer all parts of the following question about genes: PLEASE MAKE A PUNNETT SQUARE 1. For the following cross: Aa Bb cc Dd x Aa Bb CC Dd what is the chance of obtaining an individual who: a) shows all dominant traits? b) shows all recessive traits? c) is phenotypically like the second parent? d) is genotypically like the second parent? e) is heterozygous for all alleles? PLEASE MAKE A PUNNETT SQUAREGregor Mendel discovered the basis of heredity with his sweet pea plant experiments. In his studies, he determined that certain traits, such as pod color and pea shape, express complete dominance. A cross occurs between a plant with heterozygous yellow pods and wrinkled peas and a plant with green pods and heterozygous round peas. What is the probability that the offspring will exhibit recessive genes for both traits? A - 1/2B - 1/4C - 1/8D - 1/16
- Two organisms, AABBCCDDEE and aabbccddee, are mated to produce an F1 that is self-fertilized. If the capital letters represent dominant, independently assorting alleles: (a) how many different genotypes will occur in the F2? 3^5=243(AaBbCcDdEe) (b) what proportion of the F2 genotypes will be recessive for all five loci? (c) would you change your answers (a and/or b) if the initial cross occurred between AAbbCCddee X aaBBccDDEE parents? (d) would you change your answers (a and/or b) if the initial cross occurred between AABBCCDDEE X aabbccddEE parents?PEDIGREE ANALYSIS ANSWER THE FOLLOWING QUESTIONS 1. The chart shows a family's pedigree for Hitchhikers Thumb. Is this trait dominant or recessive? 2. How do you know? 3. How are individuals III-1 and III-2 related? 4. How would you name the two individuals that have Hitchhiker"s thumb? 5. Name the 2 individuals that were carriers of Hitchhiker's Thumb. 6. Is it possible for individual IV-2 to be a carrier? Why?Use the following parents to create a Punnet Square and answer the question. Cross a heterozygous father with a homozygous recessive mother. (you can use the letter A for your parental genotypes) What percent of the offspring will be homozygous recessive?
- Fill in the punnett square and answer the questions. R = round, r = wrinkled, Y = yellow, y = green. Ry Ry ry ry RY Ry RY Ry Genotype: RRYy phenotype: yellow and round 2. Is this a monohybrid or a dihybrid cross? 3. What are the two dominant alleles? 4. What are the two recessive alleles?A couple who are about to get married learn from studying their family histories that, in both their families, theirunaffected grandparents had siblings with cystic fibrosis(a rare autosomal recessive disease).a. If the couple marries and has a child, what is theprobability that the child will have cystic fibrosis?b. If they have four children, what is the chance that thechildren will have the precise Mendelian ratio of 3:1 fornormal:cystic fibrosis?c. If their first child has cystic fibrosis, what is theprobability that their next three children will be normal?Use the following information to answer the next four questions. Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Part A: Record the phenotypes and the phenotype ratio in lowest terms. Part B: Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these…