
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Question
Perform Dijkstra’s algorithm (while (Q is not empty){...}, where Q is
a min priority queue) on the following graph for source node “s”, writing out
every execution of the RELAX function, the update to the priority queue and the
updates of distance from the source node and parent for the currently visited node.
a min priority queue) on the following graph for source node “s”, writing out
every execution of the RELAX function, the update to the priority queue and the
updates of distance from the source node and parent for the currently visited node.

Transcribed Image Text:S
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- Explain the difference of A* algorithm from Dijkstra’s algorithmusing pseudo-code for the RELAX function (i.e. how the estimate of the distancefrom the source node is updated). Explain the meaning of variables in thatfunction.arrow_forwardComputer Networks The book demonstrated that a poisoned reverse will prevent the count-to-infinity problem caused when there is a loop involving three directly connected nodes. However, other loops are possible. Will the poisoned reverse solve the general case count-to-infinity problem encountered by Bellman-Ford? Yes, the poisoned reverse will prevent a node from offering a path that includes preceding nodes in the loop. It will not, preceding nodes may still be used in the computation of the distance vector offered by a given node.arrow_forward1 6 0 2 4 7 3 5 Graph Garrow_forward
- The book demonstrated that a poisoned reverse will prevent the count-to-infinity problem caused when there is a loop involving three directly connected nodes. However, other loops are possible. Will the poisoned reverse solve the general case count-to-infinity problem encountered by Bellman-Ford? -Yes, the poisoned reverse will prevent a node from offering a path that includes preceding nodes in the loop. -It will not, preceeding nodes may still be used in the computation of the distance vector offered by a given node.arrow_forwarda.Given the steps of Kruskal’s algorithm, analyze each loop and find its running time cost in terms of V and E. MST-KRUSKAL(G,w) A ← for each vertex v V MAKE-SET(v) sort E into non-decreasing order by w for each (u, v) taken from the sorted list if FIND-SET(u) FIND-SET(v) then A ← A {(u, v)} UNION(u, v) return A b. What is the total asymptotic running time of Kruskal’s algorithmarrow_forwardProve that a minimum spanning tree of a graph component must include a shortest edge. It is possible, in Dijkstra’s algorithm, that an edge removed from the priority queue is not useful: it takes us to a previously visited node. Some of these extraneous edges can be avoided by not placing an edge in the priority queue if the destination has already been visited. Is it still possible to encounter an edge to a previously visited node?arrow_forward
- Problem 3. Given a node in a binary search tree, its successor is the successor node in the sorted order determined by an inorder tree traversal. Use pseudo codes to write a function BST-Successor, which returns the successor node of a given node in a BST. You may assume that all the BST regular operation functions are existed and can be used for your function.arrow_forwardLet T : P −→ L be a function that inputs a perfect binary tree and outputs a list of vertices, defined as follows. B. If X is a binary tree consisting only of a single vertex v, then T (X ) = v, a list with only one entry. R. If X is a binary tree with root v, left subtree Xl and right subtree Xr , then T (X ) equals the list T (Xl ), T (Xr ), v.arrow_forward
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