Plot (using appropriate scaling, with titles, axis labels, and units where applicable) the absorbance versus the concentration of each standard on graph paper.
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- A green solution containing Ni+2 ions absorbs 580 nm light. Undiluted, a sample of this solution sampled in a 1.00 cm diameter cuvette has an absorbance of 0.9765 a.u.. If the molar absorptivity coefficient for Ni+2 is 6.3 x 104 M -1 cm -1 at 580 nm, how much of the original stock Ni+2 solution (in mL) needs to be added to water to create a total dilute solution volume of 10.00 mL that measures an absorbance of 0.146 a.u. at 580 nm? Report your answer to 3 significant figures. Do not include the "mL' unit label in your responseAt 21 °C, a solution of 12 mL each of 0.00200 M Fe3+ and 0.001000 M SCN- was mixed and brought to 25.0 mL with 0.1 M HNO3. The absorbance at 450 nm was measured to be 0.350 (A450 = 0.350). This solution was then heated to 45 °C and the absorbance at 450 nm was measured to be 0.142 (A450= 0.142). Is the reaction: Fe3+(aq) + SCN -(aq) → FeSCN2+(aq) exothermic or endothermic? Explain.A 10.00 mL of natural water sample containing Ni2+ was pipetted into a volumetric flask and diluted to 50.00 mL with pure water. In the second 10.00 mL of natural water sample transferred into a volumetric flask, exactly 4.00 mL of a Ni2+ solution with a concentration of 5.99 mg/L was added and then diluted to 50.00 mL with pure water. The measured absorbance is A1= 0.436 and A2 = 0.663. What is the Ni2+ concentration in unit of mg/L in the natural water sample?
- 5.00 mL of stock solution is diluted to 25.00 mL, producing solution ALPHA. 10.00 mL of solution ALPHA is diluted to 25.00 mL, resulting in solution BETA. 10.00 mL of solution BETA is then diluted to 25.00 mL, producing solution GAMMA. dilution factor for ALPHA from stock solution = 0.167 dilution factor for BETA from ALPHA solution = 0.0476 part c and d?A copper(II) sulfate solution of unknown concentration is placed in a colorimeter and an absorbance reading of 0.46 is recorded. Using the same solution cell, a 0.055 Μ solution of copper(II) sulfate gives an absorbance reading of 0.34. What is the concentration of the first solution?The absorbance values at 250nm of 5 standard solutions, and sample solution of a drug are given below: Conc. (ug/ml) A 250 nm10 0.16820. 0.32930 0.50840. 0.66050 0.846Sample. 0.661Calculate the concentration of the sample
- For the determination of Fe3 +, 25 mL of sample taken from sea water is diluted to 100 mL and a quantity of the obtained solution is taken and Fe3 + is determined by atomic absorption spectrophotometer. The absorbance values of the standard and sample solutions are below, and calculate the Fe3 + concentration in sea water in mg / L by drawing the relevant graph.Solution Absorbance1 mg / L Fe3 + 0.04095 mg / L Fe3 + 0.205110 mg / L Fe3 + 0.411615 mg / L Fe3 + 0.620820 mg / L Fe3 + 0.8222Sample Solution 0.5155In the determination of Pb in a contaminated fishmeal, 5.08 g of sample was weighed. Digestion with acids was applied and brought to dryness. Then it was made up to 10 mL and the absorbance was measured, obtaining a value of 0.013. The concentrations of the calibration curve made in ug/L are: 0.011; 0.022; 0.042 and 0.084 and the absorbances are: 0.001; 0.004; 0.009 and 0.020. Calculate the concentration of Pb in the sample in ug/kg and the % of Pb in the fishmeal.Determine the concentration of your prepared Iron (III) Salicylate Dianion solution (pure ASA) in the 10.0 mL of 1.0 M NaOH in mg/mL (Part D) using Beer's Law plot. Hint:You need to use the measured absorbance reading of your prepared Iron (III) dianion (absorbance reading: 0.83). Information from the plot: Standard: Concentration ofASA in Standards (mg/mL) A: 0.18 B: 0.14 C: 0.10 D: 0.070 E: 0.040 Mass of salicylic acid (g) 0.17g Volume of acetic anhydride (mL) 0.34mL Mass of filter paper (g) 0.35gMass of "impure" ASA and filter paper (g) 0.49g Mass of prepared "impure" ASA (g) 0.14g Melting point range of prepared ASA (°C) 20.9 °C Melting point range of standardASA (°C) 18.5°C Percent purity: 28.57% Percentage yield: 66.7% Chemical equation: C7H6O3 + C4H6O3pure ASA knowing that two consecutive dilutions were done to prepare the solution. Show all of your work.C9H8O4 + C2H4O2 b) Then, calculate the mass (in mg) of
- Caffeine, C8H10O2N4 H2O (MW = 212.2 g/mol) has been shown to have an average absorbance of 0.644 for a concentration of 1.783 mg per 100 mL at 272 nm. A sample of 3.658 g of a soluble coffee product was mixed with water to a volume of 500 mL and a 25 mL aliquot was transferred to a flask containing 25 mL of 0.1 M H2SO4. This was subjected to the prescribed clarification treatment and made up to 500 mL. A portion of this treated solution showed an absorbance of 0.666 at 272 nm. Assumbe b = 1.0 cm. Calculate the % caffeine (w/w) in the sample.The transmittance of a solution measured at 590 nm in a 1.5-cm cuvette was 76.2%. (a) What is the corresponding absorbance?(b) If the concentration is 0.0802 M, what is the absorptivity of this species at this wavelength? (c) If the absorptivity is 10,000 L mol-1 cm-1, what is the concentration?an absorbance of a solution with a pathlength of 1.00 cm is 0.544 and concentration is 1.40x10^ ^ -3 M , what is its molar absorptivity?