Problem statement In this question first we will practice function overloading and then function templates. Please follow below instructions. We can extend multiplication easily for string types if we interpret the operation as repetition. For example "code" * 3 may be interpreted as "codecodecode". In fact, languages like PythonLinks to an external site. already support this operation. Write a C++ function named multiply that can multiply(repeat) an std::string by a given integer number and return the repeated string. Write another C++ function named multiply that can multiply two given integer (int type) numbers and return the product as an integer. Write another C++ function with the same name that can multiply a floating point number (double type) by a given integer number and return the product as a floating point number. We defined three functions with the same name without a problem. It is either because they have a different number of parameters, or because any of their parameters are of a different type. This allows the compiler to recognize which one to consider; each function is unique though the names are same. What if we can write a single function that can handle all three data types and give the results accordingly? We can do so using C++ function templates. Write a C++ function template named multiply_type that can take any floating point number(double type) or integer(int type) or an std::string as the first parameter and any integer number as the second and returns the respective product of the two. Do the following Write your algorithm as code comments. I recommend to follow UMPIRE technique Implement your functions In your driver program, test your function for the criteria given below. Criteria Test # input Output 1 10 10 100 2 4 6 24 3 2.8 10 28.0 5 "C++" 10 "C++C++C++C++C++C++C++C++C++C++" 6 "Rain" 2 "RainRain"
Problem statement In this question first we will practice function overloading and then function templates. Please follow below instructions. We can extend multiplication easily for string types if we interpret the operation as repetition. For example "code" * 3 may be interpreted as "codecodecode". In fact, languages like PythonLinks to an external site. already support this operation. Write a C++ function named multiply that can multiply(repeat) an std::string by a given integer number and return the repeated string. Write another C++ function named multiply that can multiply two given integer (int type) numbers and return the product as an integer. Write another C++ function with the same name that can multiply a floating point number (double type) by a given integer number and return the product as a floating point number. We defined three functions with the same name without a problem. It is either because they have a different number of parameters, or because any of their parameters are of a different type. This allows the compiler to recognize which one to consider; each function is unique though the names are same. What if we can write a single function that can handle all three data types and give the results accordingly? We can do so using C++ function templates. Write a C++ function template named multiply_type that can take any floating point number(double type) or integer(int type) or an std::string as the first parameter and any integer number as the second and returns the respective product of the two. Do the following Write your algorithm as code comments. I recommend to follow UMPIRE technique Implement your functions In your driver program, test your function for the criteria given below. Criteria Test # input Output 1 10 10 100 2 4 6 24 3 2.8 10 28.0 5 "C++" 10 "C++C++C++C++C++C++C++C++C++C++" 6 "Rain" 2 "RainRain"
Related questions
Question
C++ question
why I have these errors
Problem statement
In this question first we will practice function overloading and then function templates. Please follow below instructions.
- We can extend multiplication easily for string types if we interpret the operation as repetition. For example "code" * 3 may be interpreted as "codecodecode". In fact, languages like PythonLinks to an external site. already support this operation. Write a C++ function named multiply that can multiply(repeat) an std::string by a given integer number and return the repeated string.
- Write another C++ function named multiply that can multiply two given integer (int type) numbers and return the product as an integer.
- Write another C++ function with the same name that can multiply a floating point number (double type) by a given integer number and return the product as a floating point number.
- We defined three functions with the same name without a problem. It is either because they have a different number of parameters, or because any of their parameters are of a different type. This allows the compiler to recognize which one to consider; each function is unique though the names are same.
- What if we can write a single function that can handle all three data types and give the results accordingly? We can do so using C++ function templates. Write a C++ function template named multiply_type that can take any floating point number(double type) or integer(int type) or an std::string as the first parameter and any integer number as the second and returns the respective product of the two.
Do the following
- Write your algorithm as code comments. I recommend to follow UMPIRE technique
- Implement your functions
- In your driver program, test your function for the criteria given below.
Criteria
Test # | input | Output |
---|---|---|
1 | 10 10 |
100 |
2 | 4 6 |
24 |
3 | 2.8 10 |
28.0 |
5 | "C++" 10 |
"C++C++C++C++C++C++C++C++C++C++" |
6 | "Rain" 2 |
"RainRain" |
![42
43 //Replace ... with your code. Hit enter key to get more vertical space
44 // IMPLEMENT
45 #include "multiply.h"
46 std::string multiply(std::string stringl, int number) {
47
48
49
50
51
52
53 }
54
55 int multiply(int numberl, int number2) {
56
return number * number2;
multiply.h
T return value =T();
for (int i = 0; i < number; ++i) {
return value += string1;
57 }
58
59 double multiply (double numberl, int number2) {
60
return number1 * number2;
61 }
}
return return value;
1 // IMPLEMENT
2 #ifndef MULTIPLY H
3 #define MULTIPLY H
4 #include <string>
16
18
19
20
21
5 std::string multiply(std::string string1, int number);
6
7
9
// In templets, we can't separate the declaration from definition; We have to write it in a single location.
template<class T>
int multiply(int numberl, int number2);
double multiply (double numberl, int number2);
22 }
23
T multiply_type(T entityl, int number) {
// Write your code below
// You may need to initialize your return value like,
// T return value = T();
T return value = T();
for (int i = 0; i < number; ++i) {
return value += string1;
}
return return value;
#endif // MULTIPLY H
multiply_driver.cpp
// REVIEW
2 #include <iostream>
#include "multiply.h"
5 //Replace ... with your code. Hit enter key to get more vertical space
6
int main(int argc, char *argv[])
7
{
8 // Testing multiply
std::cout
multiply(101std::endl.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69991f76-d6e5-4f32-9883-cbbc5a2c7e26%2F0d72cd75-5fa9-4f8c-91b3-b11dab353912%2Fxl9oouo_processed.png&w=3840&q=75)
Transcribed Image Text:42
43 //Replace ... with your code. Hit enter key to get more vertical space
44 // IMPLEMENT
45 #include "multiply.h"
46 std::string multiply(std::string stringl, int number) {
47
48
49
50
51
52
53 }
54
55 int multiply(int numberl, int number2) {
56
return number * number2;
multiply.h
T return value =T();
for (int i = 0; i < number; ++i) {
return value += string1;
57 }
58
59 double multiply (double numberl, int number2) {
60
return number1 * number2;
61 }
}
return return value;
1 // IMPLEMENT
2 #ifndef MULTIPLY H
3 #define MULTIPLY H
4 #include <string>
16
18
19
20
21
5 std::string multiply(std::string string1, int number);
6
7
9
// In templets, we can't separate the declaration from definition; We have to write it in a single location.
template<class T>
int multiply(int numberl, int number2);
double multiply (double numberl, int number2);
22 }
23
T multiply_type(T entityl, int number) {
// Write your code below
// You may need to initialize your return value like,
// T return value = T();
T return value = T();
for (int i = 0; i < number; ++i) {
return value += string1;
}
return return value;
#endif // MULTIPLY H
multiply_driver.cpp
// REVIEW
2 #include <iostream>
#include "multiply.h"
5 //Replace ... with your code. Hit enter key to get more vertical space
6
int main(int argc, char *argv[])
7
{
8 // Testing multiply
std::cout
multiply(101std::endl.
![multiply_driver.cpp
1 // REVIEW
2 #include <iostream>
3 #include "multiply.h"
4
5 //Replace ... with your code. Hit enter key to get more vertical space
6 int main(int argc, char *argv[])
7 {
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
// Testing multiply
std::cout << multiply(10, 10) <<std::endl;
/* By exactly following the pattern above, test your function below for rest of the test cases
in the order they are given*/
std::cout <<< multiply(4, 6) <<std::endl;
std::cout << multiply(2.8, 10) <<std::endl;
std::cout << multiply("C++", 10) <<std::endl;
std::cout << multiply("Rain", 2) <<std::endl;
std::cout << "Testing template function to prove the ability to write generic (type independent) code " <<std::endl;
std::cout << multiply_type<int>(10, 10) <<std::endl;
/* By exactly following the pattern above, test your function below for rest of the test cases
in the order they are given*/
24
std::cout << multiply_type<int>(10, 10) <<std::endl;
25 std::cout << multiply_type<int>(4, 6) <<std::endl;
26 std::cout<<< multiply_type<double> (2.8, 10) <<std::endl;
27
28
29
30
31
32}
CodeCheck
std::cout << multiply_type<std::string>("C++", 10) <<std::endl;
std::cout << multiply_type<std::string>("Rain", 2) <<std::endl;
18 |
I
return 0;
Reset
Running multiply_driver.cpp
Error:
In file included from multiply_driver.cpp:3:
multiply.h: In function 'T multiply_type (T, int)':
multiply.h:18:12: error: 'value' was not declared in this scope
18 |
return value += string1;
multiply.h:18:21: error: 'string1' was not declared in this scope; did you mean 'stdin'?
return value += string1;
stdin
multiply.h:20:9: error: expected primary-expression before 'return'
20 return return value;
I
... 4. 20.0
^
L....](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69991f76-d6e5-4f32-9883-cbbc5a2c7e26%2F0d72cd75-5fa9-4f8c-91b3-b11dab353912%2Fh9tsauh_processed.png&w=3840&q=75)
Transcribed Image Text:multiply_driver.cpp
1 // REVIEW
2 #include <iostream>
3 #include "multiply.h"
4
5 //Replace ... with your code. Hit enter key to get more vertical space
6 int main(int argc, char *argv[])
7 {
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
// Testing multiply
std::cout << multiply(10, 10) <<std::endl;
/* By exactly following the pattern above, test your function below for rest of the test cases
in the order they are given*/
std::cout <<< multiply(4, 6) <<std::endl;
std::cout << multiply(2.8, 10) <<std::endl;
std::cout << multiply("C++", 10) <<std::endl;
std::cout << multiply("Rain", 2) <<std::endl;
std::cout << "Testing template function to prove the ability to write generic (type independent) code " <<std::endl;
std::cout << multiply_type<int>(10, 10) <<std::endl;
/* By exactly following the pattern above, test your function below for rest of the test cases
in the order they are given*/
24
std::cout << multiply_type<int>(10, 10) <<std::endl;
25 std::cout << multiply_type<int>(4, 6) <<std::endl;
26 std::cout<<< multiply_type<double> (2.8, 10) <<std::endl;
27
28
29
30
31
32}
CodeCheck
std::cout << multiply_type<std::string>("C++", 10) <<std::endl;
std::cout << multiply_type<std::string>("Rain", 2) <<std::endl;
18 |
I
return 0;
Reset
Running multiply_driver.cpp
Error:
In file included from multiply_driver.cpp:3:
multiply.h: In function 'T multiply_type (T, int)':
multiply.h:18:12: error: 'value' was not declared in this scope
18 |
return value += string1;
multiply.h:18:21: error: 'string1' was not declared in this scope; did you mean 'stdin'?
return value += string1;
stdin
multiply.h:20:9: error: expected primary-expression before 'return'
20 return return value;
I
... 4. 20.0
^
L....
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 4 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)