Python question, please use a docstring and have comments throughout the code Write a function makeAllStrings() that takes a 2D list (a list of lists) as a parameter and modifies it. It changes the list so that all non-string objects in the list are replaced with an empty string. Strings in the list are left unchanged, so that a list containing only strings would not be modified. The empty list should also not be modified. The function returns the number of changes made by the function in the list. Recall that you can determine if a variable var holds a string by writing type(var) == str. Please write the condition you want and not the opposite of it. Use nested for loop pattern and if-else. Remember to return the count not the list. Remember you can change the value of an item in a list by using the index operator. Below are some sample executions of the function. Use the nested loop and an if-elif in the solution. Don’t forget to include the docstring and comments. Copy and paste or screen shot the code and the nine test cases shown below in your submission.   >>> lst1 = [['one','two'],[3, 'four'],[5.5, 'six'],[7, 8.8]] # list input >>> makeAllStrings(lst1) # run function with this parameter 4 >>> lst1 # show that list was modified [['one', 'two'], ['', 'four'], ['', 'six'], ['', '']] >>> makeAllStrings(lst1) # show that the list is all string now 0 >>> lst1 [['one', 'two'], ['', 'four'], ['', 'six'], ['', '']] >>> lst2 = [['Lillian',2,9.9],['Cathrine',7,16.8],['Thersa',12,10.5]] >>> makeAllStrings(lst2) 6 >>> lst2 [['Lillian', '', ''], ['Catharine', '', ''], ['Teresa', '', '']] >>> lst3=[[1,2,3,4,5],['one','two','three'],[1.1,2.2],['four','five','six','seven'],[10]] >>> makeAllStrings(lst3) 8 >>> lst3 [['', '', '', '', ''], ['one', 'two', 'three'], ['', ''], ['four', 'five', 'six', 'seven'], ['']] >>> lst4 = [] >>> makeAllStrings(lst4) 0 >>> lst4 []

Python question, please use a docstring and have comments throughout the code

• Write a function makeAllStrings() that takes a 2D list (a list of lists) as a parameter and modifies it. It changes the list so that all non-string objects in the list are replaced with an empty string. Strings in the list are left unchanged, so that a list containing only strings would not be modified. The empty list should also not be modified. The function returns the number of changes made by the function in the list. Recall that you can determine if a variable var holds a string by writing type(var) == str. Please write the condition you want and not the opposite of it. Use nested for loop pattern and if-else. Remember to return the count not the list. Remember you can change the value of an item in a list by using the index operator. Below are some sample executions of the function. Use the nested loop and an if-elif in the solution. Don’t forget to include the docstring and comments. Copy and paste or screen shot the code and the nine test cases shown below in your submission.

>>> lst1 = [['one','two'],[3, 'four'],[5.5, 'six'],[7, 8.8]] # list input

>>> makeAllStrings(lst1) # run function with this parameter

4

>>> lst1 # show that list was modified

[['one', 'two'], ['', 'four'], ['', 'six'], ['', '']]

>>> makeAllStrings(lst1) # show that the list is all string now

0

>>> lst1

[['one', 'two'], ['', 'four'], ['', 'six'], ['', '']]

>>> lst2 = [['Lillian',2,9.9],['Cathrine',7,16.8],['Thersa',12,10.5]]

>>> makeAllStrings(lst2)

6

>>> lst2

[['Lillian', '', ''], ['Catharine', '', ''], ['Teresa', '', '']]

>>> lst3=[[1,2,3,4,5],['one','two','three'],[1.1,2.2],['four','five','six','seven'],[10]]

>>> makeAllStrings(lst3)

8

>>> lst3

[['', '', '', '', ''], ['one', 'two', 'three'], ['', ''], ['four', 'five', 'six', 'seven'], ['']]

>>> lst4 = []

>>> makeAllStrings(lst4)

0

>>> lst4

[]