Queston 2 if a Schuhin Containing 0 3199 of Grch 6H20 was passed through a Cahin exchange resin the acid hrm and Hu H liberatkd was hhahd with a standard soluhon This reguured 28-5 Cm of 013M NACH, whatis Hhe Cerreet fermula q the complex assuming that one the following Complexes is present [ Gcme,c2)' , [cCHh Ojci)" [c.cmo)*
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- A 0.501 g sample of sulfathiazole was assayed usingdiazotization with 0.1905M NaNO2 VS, using 18.7 mLof the titrant. Each mL of 0.1 M NaNO2 is equivalentto 25.53 mg of C9H9N3O2S2. What is the % purity?A piece of brass weighing 230 mg was dissolved and prepared. Excess KI was added and the liberated I2 required 24.9 mL of 0.0947 M Na2 S2O3 to reach the starch end point. What is % Cu (63.5) in the sample.*SHOW COMPLETE SOLUTION* A 4.971g sample containing the mineral tellurite was dissolved and then treated with 50.00mL of 0.03114M K2Cr2O7: 3TeO2 + Cr2O7-2 + 8H+ → 3H2TeO4 + 2Cr+3 + H2O When the reaction is complete, the excess Cr2O7-2 required a 10.05mL back-titration with 0.1135M Fe2+. Calculate the percentage of TeO2 (MM 159.6) in the sample. 6Fe+2 + Cr2O7-2 + 14H+ → 6Fe+3 + 2Cr+3 + 7H2O Answer: 13.17% TeO2
- A 0.1017-g sample of KBrO3 (MW = 167 g/mole) was dissolved in dilute HCl and treated with an unmeasured excess of KI. The liberated iodine required 39.75 mL of a sodium thiosulfate solution. Calculate the molar concentration of the Na2S2O3. BrO3 - + 6I + 6HCl → Br - + 3I2 + 6KCl + 3H2O I2 + Na2S2O3 → 2NaI + Na2S4O6 The type of redox titration reaction is ___. a. iodimetry b. bromination c. iodometry d. diazotination The role of KBrO3 in the titration is ___. a. reducing agent b. oxidizing agent c. source of Br2 d. source of I2 At the endpoint of titration, the equivalence of sodium thiosulfate is equal to the following, EXCEPT ___ . a. equivalence of KI b. equivalence of liberated I2 c. equivalence of KBrO3 d. none of the other choicesAmmonium iron(II) sulfate crystals have the following formula: (NH4)2SO4.FeSO4.nH2O . In an experiment to determine n 8.492g of the salt were dissolved and made up to 250cm^-3 of solution with distilled water and sulphuric acid. A 25.0cm^-3 portion of the solution was titrated against 0.0150 mol dm^-3 KMnO4. A volume of 22.5cm^-3 was required. Find the value of nIf 28.70 mL of 0.0200 M KMnO4 is required to titreate a 0.250 g sample of K3[Fe(C2O4)3]x3H20, what is the percent C2O42- in the complex?
- If 20.60 mL of 0.0450 M KMnO4is required to titrate a 0.500 g sample of K3[Fe(C2O4)3]⋅3H2O,⋅what is the percent C2O2−4 in the complex? Would you show work ?? thanks (!!)How many milliliters of 1.5% alcoholic dimethylglyoxime should be used to provide a36.0% excess with 0.6984 q of steel containing 2.95 wt% Ni? Assume that the densityof the dimethylglyoxime solution is 0.790 g/mL. a. How much Ni sample is present? b. How many moles Ni is present in the sample? c. How much DMG is present?1. A Cr3+ solution is electrolyzed using a current of0.365 A. What mass of Cr(s) (51.9661) is plated outafter 10 hours?2. When an aqueous solution of CuSO4 is electrolyzedcopper metal is deposited. If a constant current waspassed for 5.00 h and 404 mg of Cu (63.546) metal wasdeposited, what was the current?
- When I was a boy, I watched Uncle Wilbur measure the iron content of runoff from his banana ranch. He acidified a 25.0-mL sample with HNO3 and treated it with excess KSCN to form a red complex. (KSCN itself is colorless.) He then diluted the solution to 100.0 mL and put it in a variablepathlength cell. For comparison, he treated a 10.0-mL reference sample of 6.80 3 1024 M Fe31 with HNO3 and KSCN and diluted it to 50.0 mL. The reference was placed in a cell with a 1.00-cm pathlength. Runoff had the same absorbance as the reference when the pathlength of the runoff cell was 2.48 cm. What was the concentration of iron in Uncle Wilbur’s runoff ?31. A sample of meat scrap weighing 2.000 g is digested with concentrated H2SO4 and a catalyat. The resulting solution is made alkaline with NaOH and the liberated ammonia distilled into a 50.0 mL of 0.6700 N H2SO4. The excess then requires 30.10 mL of 0.06520 N NaOH for neutralization. What is the percentage of nitrogen in the meat?A 0.4755g sample containing (NH4)2C2O4 and inert materials was dissolved in H2O and made strongly alkaline with KOH, which is converted NH4+ to NH3. The liberated NH3 was distilled into 50.00mL of 0.05035 M H2SO4. The excess H2S04 was back-titrated with 11.13 Ml of 0.1214 NaOH. Calculate the %N in the sample. Hint: Determine the moles of titrant consumed via using the prepared titrant and subtracting the equivalent moles used in back-titration.