Read a 3-character string from input into variable inString. Declare a Boolean variable isValid and assign isValid with true if inString only contains digits. Otherwise, assign isValid with false. Ex: If the input is 050, then isValid is assigned with true, so the output is: Good string Ex: If the input is h61, then isValid is assigned with false, so the output is: Bad string Note: Use getline(cin, inString) to read the entire line from input into inString #include #include #include using namespace std; int main() {    string inString;        /* Your code goes here */    if (isValid) {       cout << "Good string" << endl;    }    else {       cout << "Bad string" << endl;    }    return 0; }

Extend to cast the double to an integer, and output that integer.  Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy Howdy z 3.77 99 3.77 cast to an integer is 3

Use Character.isDigit(c) Have the user enter a password. The code loops through each character in the string. Add code in the middle section to count how many digits, uppercase and lowercase characters there are. If they have at least one of each, print that their password is ok, otherwise print that the password is not strong.Your program should prompt the user with the following. Enter Password: Below is sample input to test your program.  secret Your program should output the following Not Strong   Skeleton:  import java.util.Scanner; public class Main {   public static void main(String[] args) {      Scanner scan = new Scanner(System.in);       System.out.println("Password: ");      String password = scan.nextLine();            int upperTotal = 0;      int lowerTotal = 0;      int digitTotal = 0;            for (int i = 0; i < password.length(); ++i) {         char c = password.charAt(i);                            // Code to count what character c is here          // Do not…

The expressions string[0] and string[:1] are the same. Select one:   True False