S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect or depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with Alzheimer's. She obtains a sample of n = 30 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 28.9 with standard deviation of s = 5.94. In the general population of Alzheimer's patients, the standardized test is known to have a population mean of = 29.7. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following, select the correct null and alternative hypotheses for this study: Ho: PSAM-e 2 29.7; H1: PSAM-e < 29.7 Ho: PSAM-e < 29.7; H1: PSAM-e > 29.7 Ho: HSAM-e = 29.7; H1: HSAM-e + 29.7 Ho: MSAM-e 2 29.7; H1: MSAM-e > 29.7 Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees of freedom. There are degrees of freedom.
S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect or depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with Alzheimer's. She obtains a sample of n = 30 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 28.9 with standard deviation of s = 5.94. In the general population of Alzheimer's patients, the standardized test is known to have a population mean of = 29.7. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following, select the correct null and alternative hypotheses for this study: Ho: PSAM-e 2 29.7; H1: PSAM-e < 29.7 Ho: PSAM-e < 29.7; H1: PSAM-e > 29.7 Ho: HSAM-e = 29.7; H1: HSAM-e + 29.7 Ho: MSAM-e 2 29.7; H1: MSAM-e > 29.7 Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees of freedom. There are degrees of freedom.
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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Transcribed Image Text:S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on
depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with
Alzheimer's. She obtains a sample of n =
30 patients and asks each person to take the suggested dosage each day
for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a
21-item, multiple-choice self-report inventory for measuring the severity of depression.
The scores from the sample produced a mean of M = 28.9 with standard deviation of s =
5.94. In the general
population of Alzheimer's patients, the standardized test is known to have a population mean of u = 29.7. Because
there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these
patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis.
From the following, select the correct null and alternative hypotheses for this study:
Ho: PSAM-e > 29.7; H1: µSAM-e < 29.7
Ho: PSAM-e < 29.7; H1: µSAM-e > 29.7
Ho: HSAM-e =
29.7; H1: HSAM-e + 29.7
Ho: MSAM-e 2 29.7; H1: MSAM-e > 29.7
Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to
determine the degrees of freedom. There are
degrees of freedom.
Transcribed Image Text:Use the t distribution table to find the critical region for a = .05.
To see the table, click on the arrow and then on the words "The t Distribution" that appear in the space below
The critical t scores (the values that define the borders of the critical region) are
The estimated standard error is
The t statistic is
The t statistic
in the critical region. Therefore, the null hypothesis
rejected.
Therefore, the researcher
conclude that SAM-e has a significant effect on the moods of Alzheimer's
patients.
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