2. Show the organic product formed when methyl propanoate is reacted with lithiumdiisopropyl amide, then methyl ethanoate is slowly added to the mixture. The mixture isneutralized with aqueous acid to obtain a neutral product.(A) Show the steps in the mechanism as reactant is converted to final product. showappropriate arrow pushing and any charges.(B) Draw a box around the final product.

Lithium diisopropyl amide is a very strong base due to presence of negative charge on nitrogen atom.…

Answered: Show the organic product formed when…

Show the organic product formed when methyl propanoate is reacted with lithium sopropyl amide, then methyl ethanoate is slowly added to the mixture. The mixture

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter14: Elimination

Section: Chapter Questions

Problem 9E

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Question

2. Show the organic product formed when methyl propanoate is reacted with lithium
diisopropyl amide, then methyl ethanoate is slowly added to the mixture. The mixture is
neutralized with aqueous acid to obtain a neutral product.
(A) Show the steps in the mechanism as reactant is converted to final product. show
appropriate arrow pushing and any charges.
(B) Draw a box around the final product.

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