Solve the given problem. Show solutions if solved manually or show the Excel computation results. Follow the steps for hypothesis testing. PROBLEM : Two samples of rats are timed for their maze running time. One group is taking a drug and the other is not. The times are given in the following table: Rats with drug Rats w/o drug 15 11 12 13 13 12 10 11 11 Determine whether the use of the test drug results in a different maze running time. Use the .05 level of significance.

Based from the photo, This is the step1, so step 2 and step 3 and Step 4 must be answered. (Step 2: Test Statistic -Pearson's r correlation coefficient AND Step 3: Critical Values, and Step 4: Solve For the test stat) so based it from the photo. The table shows the number of hours spend by 30 students in studing and their test scores. Solve for the Pearson’s r and interpret the results. Use 5% significance level. Step 1: Null and Alternative Hypothesis Ho: r = 0; There is no significant relationship between the number of hours spent studying and the students test scores. Ha: r ≠ 0; There is a significant relationship between the number of hours spent studying and the students test scores. Step 2: Test Statistic -Pearson's r correlation coefficient Step 3: Critical Values, Step 4: Solve For the test stat PLEASE SHOW ME COMPLETE SOLUTIONS AND CORRECT ANSWERS THANK YOU!! It was a pleasure to me. HIGHLIGHT STEP 4: (step 4 is must)!!

Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80H0:p=0.80 versus Ha:p≠0.80Ha:p≠0.80 and calculates a test statistic of 1.10 with a pp-value of 0.273. Which of the following best represents the meaning of the pp-value?     If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273. A If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273. B If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273. C If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273. D If the…

Please solve for G, H, and I.

You are interested in investigating the efficacy of a new pain medication and design an experiment measuring pain levels before and after the administration of a new medication. You recruit 9 people to participate in your study and bring the same 9 participants in for two separate sessions. Here is the raw data: Pair Number Placebo Pain Score Pain Medication Pain Score 1 2 4 5 6 7 8 9 5 7 10 5 8 7 8 6 8 QUESTION 20 5 5 8 4 4 3 5 3 2 Use the t-test handout printout provided to calculate the t- statistic. What is the t-test statistic value? Round to the nearest tenth. What conclusion would you make on the above data, based on the t-value you calculated and the critical value of t? O You accept the null hypothesis because the t-value you calculated is inside the bounds of the critical t-value O You reject the null hypothesis because the t-value you calculated is inside the bounds of the critical t-value O You reject the null hypothesis because the t-value you calculated is outside the…

A. Find the first quartile B. Find the 2nd quartile C. Find the 3rd quartile

Need help with #19

1.) Write your solution A. Determine the 1" quartile, 2 quartile, 3rd quartile and interquartile range (IQR), given the scores of; 11, 24, 23, 11, 13, 17, 15, 19, 21, then interpret each of your answer. B. Solve for the Percentile Rank of 17.

This is the step1, so step 2 and step 3 must be answered. (Step 2: Test Statistic -Pearson's r correlation coefficient AND Step 3: Critical Values ) so based it from the photo. Show COMPLETE SOLUTIONS. The table shows the number of hours spend by 30 students in studing and their test scores. Solve for the Pearson’s r and interpret the results. Use 5% significance level. Step 1: Null and Alternative Hypothesis Ho: r = 0; There is no significant relationship between the number of hours spent studying and the students test scores. Ha: r ≠ 0; There is a significant relationship between the number of hours spent studying and the students test scores.