Sp eSantaFe | Santa Fe College | Ga XSE This is the link to your ALEKS Ho XA ALEKS - Natalie Drury - LearnG A major component of gasoline xA www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IJgt8PIGunmDn7WsVrRAXK6XnHkiRvH2tl800vdbuH6lkCnssocifJxkN3ax2TWa6AXXqcyFaLE6ceOfbJICanm28fOOHzO CHEMICAL REACTIONSSolving for a reactant using a chemical equationNatalieA major component of gasoline is octane (C,H,8). When octane is burned in air, it chemically reacts with oxygen gas (0,) to produce carbon dioxide (CO,)18and water (H,0).What mass of water is produced by the reaction of 3.05 g of octane?Round your answer to 3 significant digits.x10ExplanationCheck2020 McGraw-Hill Education. All Rights Reserved, Terms of Use | Privac

Please find below the balanced reaction taking place C8H18 + 12.5 O2 ----- > 8 CO2 + 9 H2O…

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Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter2: Basic Statistical Analysis With Excel

Section: Chapter Questions

Problem 12P

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A. B. and C. already solved (https://www.bartleby.com/questions-and-answers/chemistry-question/a89691d6-2162-4677-b0cc-dc84fcceda08). Please answer E, F and GCircle in pencil in the image on th eirght cide of the diagram is a "2"( Pb(NO3)2 ).
How do you convert 18.8 CP2/TM3 to YY2/ZW3? Use the folowing inequalities: 1CP=2.104 BX, *Bx=4 YY, 1TM=7.1088DD, 1DD=4.966ZW. When writing out the answer leave out the units.
You can use this as your reference: https://www.youtube.com/watch?v=2J2t5FRnMtM
In a river with a constant flow rate, the factory releases wastewater containing NaCl at a concentration of 200 mmol / L to the river at 20.0 L / s. The Na+ and Cl- concentrations at the downstream observation point were 1.00 mmol / L and 0.800 mmol / L, respectively. What is the river flow Q and Cl- concentration before the inflow of drainage? The river originally contains 0.500 mmol / L of Na+.
a) 80°C, 40.0 kPab) 100°C, 120.0 kPac) -10°C, 66.7 kPa
Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.
A student dissolves 10.3g of ammonium nitrate NH4NO3 in 300.g of water in a well-insulated open cup. He then observes the temperature of the water fall from 22.0°C to 19.3°C over the course of 3.1 minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction: NH4NO3s -> NH+4aq + NO−3aq You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to the correct number of significant digits. Is this reaction exothermic, endothermic, or neither? If you said the reaction was exothermic or endothermic, calculate the amount of heat that was released or absorbed by the reaction in this case. Calculate the reaction enthalpy ΔHrxn per mole of NH4NO3.
ᴀ ꜱᴛᴇᴇʟ ᴛʀᴀɪɴ ʀᴀɪʟ ɪꜱ 400 ᴍᴇᴛᴇʀꜱ ʟᴏɴɢ, ɪɴ ᴍᴀʀᴄʜ ɪᴛ ɪꜱ -30 ᴅᴇɢʀᴇᴇ ᴄ ᴀɴᴅ 40 ᴅᴇɢʀᴇᴇ ᴄ ɪɴ ᴊᴜʟʏ. ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ᴄʜᴀɴɢᴇ ɪɴ ʟᴇɴɢᴛʜ ɪɴ ᴍᴍ? ᴋ ꜰᴏʀ ꜱᴛᴇᴇʟ = 11.7 x 10^-6 ᴍ/ᴍ-ᴄ
https://cxp.cengage.com/contentservice/assets/owms01h/references/chemtables/genChemIndex.html
You take a representative soil sample and determine the following data: Exchangeable cation cmolc/kg of soil Ca2+ 2.7 Mg2+ 1.0 K+ 0.1 H+ 1.0 Al3+ 2.8 Na+ 0.1 1) What is the CEC (cmolc/kg ) of this soil?
When concentrated nitric is sold, the label contains no mention of the molarity of the acid. Instead, the label normally lists the concentration of nitric acid as a wt/wt percent and gives the specific gravity of the solution. If the solution is 68.0 (wt/wt %) and nitric acid and has a specific gravity of 1.41 kg/L, calculate the molarity of 68.0 % concentrated nitric acid. FW HNO3=63.01g/mol
1. What is the mEq of silver nitrate? 170 0.0170 0.170 17.0 2. How much (mL) silver nitrate is required for the standardization? 4.995 49.950 49.590 45.990 * MW of silver nitrate = 170 g/mol * Please take note that Im looking for the silver nitrate

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