Task - Using pointers to process arrays (C Language) Example #5 below expected output is 45, but from the program below its coming out to 46. Please help make it come out to 45 as expected In a TV show, each minute can be either interesting or boring. Assume that if 7 consecutive minutes are boring, then an average viewer will stop watching the show. Write a C program that calculates how many minutes that an average viewer will watch a TV show, given the interesting minutes. Assume the TV shows are 45 minutes long. Requirements Name your program project4_minutes.c. Follow the format of the examples below. The program will read in the number of interesting minutes, then read in the interesting minutes. The program should include the following function. Do not modify the function prototype. int find_minute(int *minutes, int n); minutes represents the input array for interesting minutes, n is the length of the array (the number of interesting minutes). The function returns the how many minutes an average viewer will watch the show. This function should use pointer arithmetic– not subscripting – to visit array elements. In other words, eliminate the loop index variables and all use of the [] operator in the function. In the main function, call the find_minute function and display the result. Pointer arithmetic is NOT required in the main function. Examples (your program must follow this format precisely) Example #1 Enter the number of interesting minutes: 3 Enter the interesting minutes: 7 13 28 Output: 20 Note: In the first example, minutes 14, 15, 16, 17, 18, 19, 20 are all boring and thus an average viewer will stop watching after the 20th minute. So, the average viewer will watch for 20 minutes. Example #2 Enter the number of interesting minutes: 3 Enter the interesting minutes: 7 13 18 Output: 25 Note: In the second example, minutes 19, 20, 21, 22, 23, 24, 25 are all boring and thus an average viewer will stop watching after the 25th minute. So, the average viewer will watch for 25 minutes. Example #3 Enter the number of interesting minutes: 6 Enter the interesting minutes: 9 13 28 32 38 42 Output: 7 Note: In the third example, minutes 1, 2, 3, 4, 5, 6, 7 are all boring and thus an average viewer will stop watching after the 7th minute. So, the average viewer will watch for 7 minutes. Example #4 Enter the number of interesting minutes: 6 Enter the interesting minutes: 5 12 18 24 31 38 Output: 45 Note: In the fourth example, there are no consecutive 7 boring minutes So, the average viewer will watch for the whole 45 minutes. Example #5 Enter the number of interesting minutes: 8 Enter the interesting minutes: 2 9 13 20 25 29 33 39 Output: 45 Program- #include //Function prototype int find_minute(int *minutes, int n); int main(){ int minutes[100]; int n; //Ask user to enter the value printf("Enter the number of interesting minutes: "); scanf("%d", &n); printf("Enter the interesting minutes: "); //Read the interesting minutes for(int i = 0; i < n; i++){ scanf("%d", &minutes[i]); } //Call the function int result = find_minute(minutes, n); //Print the result printf("Output: %d\n", result); return 0; } //Function definition int find_minute(int *minutes, int n){ //start of the tv show at 0 int currTime = 0; //Iterating using pointer arithmetic // minutes+i is equivalent to &minutes[i] for(int i = 0; i < n; i++){ if(*(minutes+i) <= currTime+7){ currTime = *(minutes+i); } else{ break; } } int result; if(currTime < 45){ result = currTime + 7; } else{ //Show stops at 45 minutes, result should not be greater than 45 result = 45; } return result; }
Task - Using pointers to process arrays (C Language)
Example #5 below expected output is 45, but from the
In a TV show, each minute can be either interesting or boring. Assume that if 7 consecutive minutes are boring, then an average viewer will stop watching the show. Write a C program that calculates how many minutes that an average viewer will watch a TV show, given the interesting minutes. Assume the TV shows are 45 minutes long.
Requirements
- Name your program project4_minutes.c.
- Follow the format of the examples below.
- The program will read in the number of interesting minutes, then read in the interesting minutes.
- The program should include the following function. Do not modify the function prototype.
int find_minute(int *minutes, int n);
-
- minutes represents the input array for interesting minutes, n is the length of the array (the number of interesting minutes). The function returns the how many minutes an average viewer will watch the show.
- This function should use pointer arithmetic– not subscripting – to visit array elements. In other words, eliminate the loop index variables and all use of the [] operator in the function.
- In the main function, call the find_minute function and display the result.
- Pointer arithmetic is NOT required in the main function.
Examples (your program must follow this format precisely)
Example #1
Enter the number of interesting minutes: 3
Enter the interesting minutes: 7 13 28
Output: 20
Note: In the first example, minutes 14, 15, 16, 17, 18, 19, 20 are all boring and thus an average viewer will stop watching after the 20th minute. So, the average viewer will watch for 20 minutes.
Example #2
Enter the number of interesting minutes: 3
Enter the interesting minutes: 7 13 18
Output: 25
Note: In the second example, minutes 19, 20, 21, 22, 23, 24, 25 are all boring and thus an average viewer will stop watching after the 25th minute. So, the average viewer will watch for 25 minutes.
Example #3
Enter the number of interesting minutes: 6
Enter the interesting minutes: 9 13 28 32 38 42
Output: 7
Note: In the third example, minutes 1, 2, 3, 4, 5, 6, 7 are all boring and thus an average viewer will stop watching after the 7th minute. So, the average viewer will watch for 7 minutes.
Example #4
Enter the number of interesting minutes: 6
Enter the interesting minutes: 5 12 18 24 31 38
Output: 45
Note: In the fourth example, there are no consecutive 7 boring minutes So, the average viewer will watch for the whole 45 minutes.
Example #5
Enter the number of interesting minutes: 8
Enter the interesting minutes: 2 9 13 20 25 29 33 39
Output: 45
Program-
#include <stdio.h>
//Function prototype
int find_minute(int *minutes, int n);
int main(){
int minutes[100];
int n;
//Ask user to enter the value
printf("Enter the number of interesting minutes: ");
scanf("%d", &n);
printf("Enter the interesting minutes: ");
//Read the interesting minutes
for(int i = 0; i < n; i++){
scanf("%d", &minutes[i]);
}
//Call the function
int result = find_minute(minutes, n);
//Print the result
printf("Output: %d\n", result);
return 0;
}
//Function definition
int find_minute(int *minutes, int n){
//start of the tv show at 0
int currTime = 0;
//Iterating using pointer arithmetic
// minutes+i is equivalent to &minutes[i]
for(int i = 0; i < n; i++){
if(*(minutes+i) <= currTime+7){
currTime = *(minutes+i);
}
else{
break;
}
}
int result;
if(currTime < 45){
result = currTime + 7;
}
else{
//Show stops at 45 minutes, result should not be greater than 45
result = 45;
}
return result;
}
Introduction
The given question is asking for a program that calculates the maximum number of minutes an average viewer will watch a TV show given the number of interesting minutes. The program assumes that if there are 7 consecutive minutes of boring content, then the average viewer will stop watching the show. The user is prompted to enter the number of interesting minutes, followed by the interesting minutes themselves.
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