The data for a random sample of six paired observations are shown in the table.a.Calculatex and sb. Express μ in terms of μ, and μ₂-c. Form a 90% confidence interval for Hd.d. Test the null hypothesis Ho: H = 0 against the alternative hypothesis H₂: #0. Use α=0.10.a. Calculate the difference between each pair of observations by subtracting observation from observation 1. Find X-(Round to two decimal places as needed.)(-)Pair1256Population 1 Sample(Observation 1)51211633Population 2 Sample(Observation 2)3Q

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher who wants to know whether the proportion of male births in a hospital is different from the established baseline of 51.07%, would like to test the following hypotheses: Ho:P = 0.51 vs. Ha :P = does not equal 0.51 a) Is the alternative hypothesis upper tail, lower tail, or two tailed? b) What do you conclude if the test results p-value of 0.03 at alpha value = 5% c) What do you conclude if the test results p-value of 0.08 at alpha value = 10%
b) Find the critical value of t for a 90% confidence interval with df=58.
Assume we wanted to show that the true proportion of virginica iris seeds that fail to germinate is less than 20%. Let's say we tested at an alpha of 0.05, and found a p-vale of 0.082. Which of the following would be an appropriate conclusion and interpretation? A) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state we have insufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. B) With an alpha of 0.05, and a p-value of 0.0082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. C) With an alpha of 0.05, and a p-value of 0.082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. D) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state…
In a hypothesis test with hypotheses Ho: μ ≤ 54 and H1: μ > 54, a random sample of 24 elements selected from the population produced a mean of 58.6 and a standard deviation of 13.4. The test is to be made at the 10% significance level. Assume the population is normally distributed. What is the critical value of t ?
In an exercise with silicon nanopillars based on the z-test of a large sample n = 50 with X-Bar = 305.58 and s = 36.971 A) Construct a confidence interval for the 95% mean. B) Decide whether or not to reject the null hypothesis mu = 310 nm against the alternative hypothesis mu different to 310 nm with alpha = 0.05. C) What is your decision in the previous section if alpha = 0.02
A random sample of n measurements was selected from a population with unknown mean μ and standard deviation σ=35 for each of the situations in parts a through d. Calculate a 95% confidence interval for μ for each of these situations. a. n=50, x=27 b. n=150, x=118 c. n=120, x=15 d. n=120, x=5.36 a. (enter your response here,enter your response here)
1. The following table illustrates the BMI for a number of patients recently enrolled in a study investigating the relationship between BMI and type 2 diabetes. Participant BMI (kg/m2) A 26.5 B 19.2 C 29.7 D 27.4 E 30.2 F 28.9 A) Assuming the participants can be considered to be normally distributed, and that they comefrom a population with a σ=2.4 kg/m2, calculate a 95% confidence interval for the mean BMI ofthe population for which they represent.B) Correctly interpret the confidence interval you found above.
Recently, the annual number of driver deaths per 100,000 for the selected age groups was as follows: Age Number of Driver Deaths per 100,000 16–19 38 20–24 36 25–34 24 35–54 20 55–74 18 75+ 28 Use the 4 steps of hypothesis testing to see if the prediction is significant with a criteria of alpha=.05 on the following data For each age group, pick the midpoint of the interval for the X value. (For the 75+ group, use 80.)
assume that you have a sample of n1=9, with the sample mean x1=50, and a sample standard deviation of S1=5, and you have an independent sample of n2=15 from another population with a sample mean of X2=31, and the sample deviation S2=7. Construct a 99% confidence interval estimate of the population mean difference between u1 and u2. Assume that the two population variances are equal.
A random sample of 10 professional athletes produced the following data where X is the number of endorsements the player has and Y is the amount of money made (in millions of dollars). Use the 4 steps of hypothesis testing to see if the prediction is significant with a criteria of alpha=.05 on the following data. x y 0 2 3 8 2 7 1 3 5 13 5 12 4 9 3 9 0 3 4 10
For a random sample of 50 measurements of X1, sample mean x ̄1 = 200, sample standard deviation s1 = 10. For X2, from a random sample of 50, sample mean x ̄2 = 190 and sample standard deviation s2 = 15. Assume that population distributions are approximately independent normal with unequal variances. Answer the following questions 1 through 3. 1. Construct a 90% confidence interval for μ1 − μ2. (i) State the assump- tions, (ii) show your work, and (iii) interpret the result in context of the problem. 2. Using the same samples, you want to test whether the difference between two population means is 5 or not at the significance level α = 0.1. H0 : μ1 − μ2 = 5 vs H1 : μ1 − μ2 ̸= 5. What would your conclusion be? Support your answer briefly. You don’t need to conduct the hypothesis test.
The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with ? = 0.32 and that x = 5.21. (Use ? = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5?State the appropriate null and alternative hypotheses. H0: ? = 5.5Ha: ? ≠ 5.5H0: ? = 5.5Ha: ? ≥ 5.5 H0: ? = 5.5Ha: ? < 5.5H0: ? = 5.5Ha: ? > 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the desired percentage.Reject the null hypothesis. There is sufficient evidence…

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