The following results were obtained by monitoring the reaction H*(ag) + l'(ag) + ½ H2O2(ag) → ½ I2(ag) + H2O [I] [H,O2] rate 0.020 0.020 3.3 x 10-5 0.040 0.020 6.6 x 105 0.060 0.020 9.0 x 105 0.040 0.040 1.3 x 10-4 Determine the order of the reaction with respect to I' and H2O2 and also determine the value for the rate constant, k

The following results were obtained by monitoring the reaction H*(ag) + l'(ag) + ½ H2O2(ag) → ½ I2(ag) + H2O [I] [H,O2] rate 0.020 0.020 3.3 x 10-5 0.040 0.020 6.6 x 105 0.060 0.020 9.0 x 105 0.040 0.040 1.3 x 10-4 Determine the order of the reaction with respect to I' and H2O2 and also determine the value for the rate constant, k

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter11: Chemical Kinetics

Section: Chapter Questions

Problem 11.33PAE: The following experimental data were obtained for the reaction of \'I14* and NOf in acidic solution....

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The acid-catalyzed iodination of acetone CH3COCH3(aq) + I2(aq) CH3COCH2I(aq) + HI(aq) is a common laboratory experiment used in general chemistry courses to teach the method of initial rates. The reaction is followed spectrophotometrically by the disappearance of the color of iodine in the solution. The following data (J. P. Birk and D. L Walters, Journal of Chemical Education, Vol. 69, p. 585, 1992) were collected at 23 C for this reaction. Determine the rate law for this reaction.
The following experimental data were obtained for the reaction of \'I14* and NOf in acidic solution. NH/(aq) + NO2-(aq) — N;(g) + 2 H,O(f) INH/I (mol L1) [NO21 (mol L-1, Rate = A[NJ/At (mol L-1 s’) 0.0092 0.098 3.33 X IO"7 0.0092 0.049 1.66 X 10‘7 0.0488 0.196 3.51 X 10"6 0.0249 0.196 1.80 X 10-6 Determine the rate law for this reaction and calculate the rate constant.
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The following results were found after following the procedure Part B in the experiment: 0.053 M I- and 0.041 M H2O2 were used Temperature (oC) Calculated Reaction Rate (M/s) 12 0.031 30 0.119 88 0.797 Assuming the Rate Law = k[I-]2[H2O2] 2 Calculate the value of k at temperature 88oC. Give your answer to 1 place after the decimal.
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4 for each temperature . 4.8 c , 22.0c , 37.4c calculate 1/t and ln (rate ) . slope = -1.96E+03. activation energy 1.63E+04 J
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The decomposition of aqueous sucrose to form the isomers glucose and fructose is a common organic reaction, which requires a strong catalyst: C12H22O11(aq) + H2O(l) → 2C6H12O6(aq). The following data were collected during the process: Time (min) [C12H22O11] (mol/L) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 (A) If we performed a new trial with an initial concentration of sucrose of 0.400 mol/L, what concentration would remain after 4.0 h has passed?
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