The results of the sieve analysis done on a soil are shown below Sieve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 31 60 0.250 20 100 0.149 18 200 0.074 4 LL 60 PL 40 Determine its classification using USCS.

The results of the sieve analysis done on a soil are shown below Sieve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 31 60 0.250 20 100 0.149 18 200 0.074 4 LL 60 PL 40 Determine its classification using USCS.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: The result of sieve analysis of three soils is given. It is required to classify these soils…

A: AASHTO soil classification system is also called as HRB or Highway Research Board soil…

Q: The following data are the results of a sieve analysis. Determine the percentage of silt and clay…

Q: Classify the soil using AASHTO Method.

A: AASHTO SOIL CLASSIFICATION:

Q: e results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760…

Q: Sieve Analysis Mass Retained Diameter The following (grams) are the Sieve No. (mm) B results of a…

A: Given We have Two types of soil samples One is -A Other one is - B We have to classify the soils…

Q: 5.9 Classify the following soils using the Unified soil classification system. Give the group…

A: Note:- Hi! Thank you for the question, As per the honor code, we are allowed to answer three…

Q: 5.9 Classify the following soils using the Unified soil classification system. Give the group…

A: The UCS soil classification table is given below

Q: Calculate the coefficient of gradation, Cc. ? Classify the soil by AASHTO and USCS system. (LL = 30,…

Q: For a soil, given e= 0.75, w= 22%, Gs= 2.66, calculate the dry density of soil in slug/ft3. Note ρ…

A: Given data Void ratio (e) = 0.75 Water content (w) = 22% = 0.22 Specific gravity of soil (Gs) =…

Q: Classify the soil using AASHTO Method.

A: AASHTO CLASSIFICATION:

Q: Q5: Classify the soil with the data in table below using USCS to find the followings 1- group symbol…

A: H

Q: eve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 40 60 0.250 31 100

A: Step1:Look at the % passing through sieve no 200=4<50%⇒COARSE GRAINED SOIL

Q: 2. The sieve analysis data for a granular soil are given below. % passing 19 mm sieve =100 % passing…

Q: 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 61 PL 26 Determine its classification using…

A: soil is classified as CH

Q: Classify the soil by AASHTO system.Justify your answer. provide fbd

A: AASHTO CLASSIFICATION:

Q: III -"Particle Size Distribution Test" Tabulation of Data: 1 4 7 Sieve Sieve Mass Mass of Mass of…

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.…

A: The classification of soil is based on the index properties of the soil such as grain size…

Q: SITUATION 1 The sieve analysis of three soils and the liquid and plastic limits of the fraction…

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.

A: To Determine Classification of the given soil data according to AASHTO soil classification system.…

Q: SITUATION: It is known that the natural soil at a construction site has a void ratio of 1.0. At the…

Q: Situation 1 A sample of soil has the following grain-size characteristics: Size (mm) * SOIL…

Q: A Soil sample has a liquidity index of 0.29, a plastic limit of 12.2%., and a plasticity index of…

Q: 5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and…

A: We have to plot dry unit weight verses relation and have to determine maximum dry unit weight and…

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve…

A: iLook at the % passing through No 200=39%>35%so Clay-silt material

Q: liquid limit and plastic limit test. Compute the plasticity index. Liquid Limit Test Wt. of Soil Wt.…

A: Given:- Liquid limit test Soil sample Weight of wet soil (kg) Weight of dry soil (kg) Number of…

Q: 2. .. ;. The sieve analysis data for a granular soil are given below. % passing 19 mm sieve =100 %…

A: To Determine percentages of gravels, sands and fines within this soil, based on the Unified Soil…

Q: Determine the percentage of gravel for the grain-size characteristics of a soil are given as…

Q: Determine its classification using USCS SP GW SW GP None of the above

A: Given, Sieve analysis data

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.…

A: Given, Sieve analysis data

Q: The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760…

A: Given Seive size and Percentage Passing through each seive. To Determine Classification of soil…

Q: For a given soil, the following are given in Table: Specific Gravity Gs, bulk unit weight γ), and…

Q: Answer ALL Questions Time: 2 Hours Q3: Classify the following soil by using the Unified soil…

A: given liquid limit= 60% and plastic limit =40% plasticity index=LL-PL Ip=LL-PLIp=60-40Ip=20%

Q: saturated soil sample, weighing 178 g has a volume of 96 cc. If the specific gravity of soil solids…

Q: Using the Unified Soil Classification System classify the following three soils: Sieve size Soil 1…

A: Solution: The unified soil classification depends on the percentage of soil passing through NO. 200…

Q: The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method.…

Q: 2. The results of the particle-size analysis of a soil are as follows: (show all the analysis…

A: Look at % passing through No 200=36%>35% so Clay and silt mineral

Q: A saturated soil sample, weighing 178 g has a volume of 96 cc. If the specific gravity of soil…

Q: ML None of the above. CL CH MH

A: soil is classified as MH

Q: Data Sieve Sieve No. Opening (mm) 4 4.750 10 2.000 20 0.850 30 0.600 40 0.425 0.250 0.106 0.075 60…

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.…

A: Given Percentage Passing through each seive size and Liquid limit LL, Plastic limit PL To Determine…

Q: 47.)

Q: 5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and…

Q: Table 1. Raw data from sieve analysis E retained mass (g) Sieve Mass of Mass of sieve + Retained…

A: Sieve Aperture (μm) Mass of sieve(g) Mass of sieve+ Retained Soil (g) Retained Mass (g)…

Q: Refer to the table below. It shows a sieve analysis of soil samples A, B, and C. Soil Sample…

Q: The sieve analysis data for a granular soil are given below. NES LECTUREY % passing 19 mm sieve =100…

Q: Classify the following soils by the AASHTO classification system. Give the group index for each soil

A: The AASHTO soil classification table is shown below:

Q: The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method.…

A: To Determine Classification of the given soil data according to AASHTO soil classification system.…

Q: 5.4 Classify the following soils by using the Unified soil classification system. Give the group…

A: For soil 1: The coarse fraction=100-30 =70% The gravel…

Q: (For Items 11-13) SITUATION. The given data shows a sieve analysis of soil samples A, B and C. The…

A: Given data,

Q: lts of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 88 6…

A: Step1:Look at the % passing through sieve no 200=14<50%⇒COARSE GRAINED SOIL

Concept explainers

Soil classification and characteristics

Soil classification is a method of categorizing soil based on its properties, types, and uses. The motive of soil classification is to arrange various types of soils and divide them into groups for various engineering and agricultural purposes. Soil classification is carried out by various agencies as per their purposes. From an engineering perspective, soil classification is done to find out the suitability of soil for various construction purposes like the construction of dams, foundations, highways, infrastructures, and so on. For engineering purposes, the soil is classified by the following systems:

Question

The results of the sieve analysis done on a soil are shown below

Sieve No.	Diameter	Soil A
4	4.760	89
6	2.380	70
10	2.000	63
20	0.840	55
40	0.420	31
60	0.250	20
100	0.149	18
200	0.074	4

LL	60
PL	40

Determine its classification using USCS.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

GEOTECHNICAL ENGINEERING: The resuts of a sieve analysis for a soil sample are given in the Table. Cc = 0.5 and Cu = 5. If the LL and the PL of the soil sample are 55 and 40 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 45 0.075 9
Subject: Soil Mechanics A. Classify the Soil Using USCS (with explanation/ justification) Given data: D10 = ? D30= 0.0023mm D60= 0.032mm Liquid Limit= 49% Plastic Limit= 24% CHOICES: a. CL (lean clay with gravel) b. CL ( lean clay with sand) c. ML (silt with gravel) d. ML (Silt with sand)
The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No.20 0.840 61 No.40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
The soil is excavated with a total of 3437.5m³ (including the swell of 25%) of soil. What is the total volume ofsoils being excavated before the swell is included?a. 2851.5m³b. 3755.5 m³c. 2578.3 m³d. 3401.8 m³
How to calculate the settlement of a group of frictionpiles in clay?
Q 03: (a) Draw graph (using graph paper or excel) for soil 1 and 2 given in problem 2 and paste it in the following?(b) Calculate D10 D30 and D60 for Sieve Analysis plot in section (a) and calculate Coefficient of Uniformity and Coefficient of curvature for both soils. Also comment if the soils are well graded or poorly graded and which soil is better graded in comparing to other in case of soil 1 and 2.
Answer no.2 question but plss adjust Correction in soil c in prob1 its 35% clay
soil mechanic. Classify the soil according to unified soil classification system USCS; if the following data is given : Passing sieve No. 200 =7% / Passing sieve No. 4 = 40% / D10= 0.18, D30= 0.69 and D60= 3/ LL-28%, Pl=19%
SHOW COMPLETE SOLUTION PLS VALUES: X = 853B = 5
Question, exaplaination.
SUBJECT: SOIL MECHANICS A. Classify the soil using USCS (with explanation) CHOICES: a. GW (well graded gravel with sand) b. SP (Poorly graded sand) c. SW(well graded sand and gravel) d. GP (poorly graded gravel) B. What is the coefficient of uniformity of the soil? a. 45 b. 65 c. 35 d. 55 B..
After the sample has been fractured and reassembled, the gage marks that initially measured 2.000” now measure 2.050”. What is the percent elongation for the sample (provide answer as %, i.e. list 15% as 15, not 0.15)?