Answer all subparts i will thumbs up... The two loads shown in (Figure 1) can be described asfollows: Load 1 absorbs an average power of 10 kW anddelivers 4 KVAR of reactive power; load 2 has animpedance of (60 + j80) N. The voltage at the terminalsof the loads is 1500/2 cos(100rt) V.0.5 0 j0.05 NL2а.Find the rms value of the source voltage.b. Determine by how much time the load voltage is out of phase with the source voltage by finding the value of(Ov, – bv,)/w, where Oy, and Ov, are the phase angles of the voltages VI and V, respectively, and w is the angularfrequency of the voltages.с.Does the load voltage lead or lag the source voltage?

Answered: Image /qna-images/answer/674cd68b-1a7d-418c-bc29-1a7e993136a8.jpg

The two loads shown in (Figure 1) can be described as ollows: Load 1 absorbs an average power of 10 kW and delivers 4 KVAR of reactive power; load 2 has an mpedance of (60 + j80) N. The voltage at the terminals of the loads is 1500/2 cos(100rt) V. 0.5 N j0.05 2 L2 Find the rms value of the source voltage. Determine by how much time the load voltage is out of phase with the source voltage by finding the value of (Ov, – Ov,)/w, where Oy, and Ov, are the phase angles of the voltages VI, and Vg respectively, and w is the angular frequency of the voltages. Does the load voltage lead or lag the source voltage?

The two loads shown in (Figure 1) can be described as ollows: Load 1 absorbs an average power of 10 kW and delivers 4 KVAR of reactive power; load 2 has an mpedance of (60 + j80) N. The voltage at the terminals of the loads is 1500/2 cos(100rt) V. 0.5 N j0.05 2 L2 Find the rms value of the source voltage. Determine by how much time the load voltage is out of phase with the source voltage by finding the value of (Ov, – Ov,)/w, where Oy, and Ov, are the phase angles of the voltages VI, and Vg respectively, and w is the angular frequency of the voltages. Does the load voltage lead or lag the source voltage?

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.30MCQ: Under balanced operating conditions, consider the three-phase complex power delivered by the...

See similar textbooks

Similar questions

If the rms phasor of a voltage is given by V=12060 volts, then the corresponding v(t) is given by (a) 1202cos(t+60) (b) 120cos(t+60) (c) 1202sin(t+60)
The two loads shown can be described as follows: Load 1 absorbs an average power of 60 kW and delivers 70 kVAR of reactive power; Load 2 has an impedance of (24+j7) Ω. The voltage at the terminals of the loads is 25002 cos 120π t V.1. a) Find the rms value of the source voltage.2. b) By how many microseconds is the load voltage out of phase withthe source voltage?3. c) Does the load voltage lead or lag the source voltage?
A load with a voltage amplitude of 50 Hz 300 V rms at its terminals consumes 28.98 kW at a back power factor of 0.69. If a 225.87 microfarad capacitor is connected parallel to the terminals of this load, how much will the amplitude of the current drawn from the line decrease?
In the given circuit, the amplitude of the input voltage is 180 Volts RMS and its phase is 45 degrees.The power values that the loads receive/give are given below.What is the phase of the current phasor I0?Load 1 = 1.8 kW and capacitive 1.2 kVAR8 kW with load 2 = 0.5 back power factorLoad 3 = 3 kVA with 0.9 forward power factor
A supply voltage v given by v = (240 sin 314t + 40 sin 942t + 30 sin 1570t) volts is applied to a circuit comprising a resistance of 12 ohmconnected in series with a coil of inductance 9.55 mH. Determine (a) an expression to represent the instantaneous value of the current, (b) the rms voltage, (c) the rms current, (d) the power dissipated, and (e) the overall power factor.
A voltage given by v(t) = 311 cos (311 pi t) V is applied to a 50-ohm resistance. (a.) Sketch v(t) to scale versus time. (b.) Determine the rms value of the voltage and the average power delivered to the resistance. (c.)Determine the power as a function of time and sketch to scale.
The voltage between the ends of a load and the current through it are given by: v (t) = 20 + 60 cos100ti (t) = 1 - 0.5 sin100t Find:The rms values of the voltage and current and the average power dissipated in the load.
Between the terminals a and b in the figure, there is a load formed by connecting the resistor R0 and inductance L0 in series. The amplitude of the voltage Vs (t) is √2 150 volt phase angle Qs = 0 degree period T = 200π microseconds. Since R = 300ohm and C = 1 microfarad A) If the load phase angle QL = 30 degrees, find the values of R0 and L0 that enable the load to draw the maximum average power from the circuit. =? B) Calculate the average power on the load. =?
1. a) Find the rms magnitude and the phase angle of ICA in the circuit shown. 2. b) What percent of the average power delivered by the three-phase source is dissipated in the three-phase load?
A Y-connected balanced three-phase source is feeding a balanced three-phase load. The voltage and current of the source coil are: Calculate the following: The rms phase voltage. The rms line-to-line voltage. The rms current in the source. The rms current in the transmission line. The frequency of the supply. The power factor at the source side, state leading or lagging. The three-phase real power delivered to the load. The three-phase reactive power delivered to the load. If the load is connected in delta configuration, calculate the load impedance.
Determine the rms values of each of the following (a) v(t) = 100 sin(ωt) V Vrms = 70.7V (b) i(t) = 8 sin(377t) A Irms = 5.656V(c) v(t) = 40 sin(ωt + 40o) V Vrms = 28.28V (d) i(t) = 120 cos(ωt) mA Irms = 84.84A Can you double check if my answer is correct?
A load absorbs 72044 W at a lagging power factor of pf = 0.67. If the current flowing through the load is Ix = 0.100 A−rms, determine the impedance of the load.