The vinyl chloride molecule is (C2H3CI)nCalculate the molecular weight of polyvinylchloride (PVC) molecule with n=D10.Given:Molar mass:• M(C)=12.01 g/mole• M(H)=1.008 g/mole• M(CI)= 35.45 g/moleSelect one:a. Molecular weight= 841.56b. Molecular weight= 3366.24c. Molecular weight3 624.94d. Molecular weight= 1683.12e. Molecular weight= 21039f. Molecular weight= 2103.9g. Molecular weight3D420.78h. Molecular weight= 8415.6

The sum of atomic weights of all the atoms of the molecule is its molecular weight.

The vinyl chloride molecule is (C2H3CI)n Calculate the molecular weight of polyvinyl chloride (PVC) molecule with n=10. Given: Molar mass: M(C)=12.01 g/mole M(H)=1.008 g/mole M(CI)= 35.45 g/mole Select one: a. Molecular weight3D 841.56 b. Molecular weight= 3366.24 c. Molecular weight= 624.94 d. Molecular weight=D 1683.12 e. Molecular weightD 21039 f. Molecular weight3 2103.9 g. Molecular weight3D420.78 h. Molecular weight= 8415.6

The vinyl chloride molecule is (C2H3CI)n Calculate the molecular weight of polyvinyl chloride (PVC) molecule with n=10. Given: Molar mass: M(C)=12.01 g/mole M(H)=1.008 g/mole M(CI)= 35.45 g/mole Select one: a. Molecular weight3D 841.56 b. Molecular weight= 3366.24 c. Molecular weight= 624.94 d. Molecular weight=D 1683.12 e. Molecular weightD 21039 f. Molecular weight3 2103.9 g. Molecular weight3D420.78 h. Molecular weight= 8415.6

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter13: Isolation Of Eugenol From Clov

Section: Chapter Questions

Problem 9Q

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