Three loads are applied to the short rectangular post shown. The cross-sectional dimensions of the post are also shown. Assume Q = 100 kN, P = 160 kN, R = 70 kN, e = 55 mm, y1 = 80 mm, y2 = 140 mm, ZK = 30 mm, b = 130 mm, d = 170 mm. Determine (a) the normal and shear stresses at point K. (b) the principal stresses and maximum in-plane shear stress at point K, and show the orientation of these stresses on an appropriate sketch. b K R ZK Y2 - ZK H H K

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
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Three loads are applied to the short rectangular post shown. The cross-sectional dimensions of the post are also shown.
Assume Q = 100 kN, P = 160 kN, R = 70 kN, e = 55 mm, yı = 80 mm, y2 = 140 mm, zK = 30 mm, b = 130 mm, d = 170 mm.
Determine
(a) the normal and shear stresses at point K.
(b) the principal stresses and maximum in-plane shear stress at point K, and show the orientation of these stresses on an
appropriate sketch.
b
R
ZK
y2
H
H
K
Transcribed Image Text:Three loads are applied to the short rectangular post shown. The cross-sectional dimensions of the post are also shown. Assume Q = 100 kN, P = 160 kN, R = 70 kN, e = 55 mm, yı = 80 mm, y2 = 140 mm, zK = 30 mm, b = 130 mm, d = 170 mm. Determine (a) the normal and shear stresses at point K. (b) the principal stresses and maximum in-plane shear stress at point K, and show the orientation of these stresses on an appropriate sketch. b R ZK y2 H H K
Part 2
Incorrectzdirectionydirection xdirection K.Combine My. Note that x. Only xdirectionz,
M,is positive. See the
produces and calculations of
equivalent
and the produce at the
the moment both
the
The
force in moments section
components components force in a
force in the
about
containing due to these produce a the
moment
moments for
the
negative the
two forces
negative
negative about
various combined
loading cases in
the examples in
negative
to
moment
determine
about
Section 15.4.
Calculate M, the moment due to the combined loading about the x direction at the section containing K. Also, calculate M, the
moment due to the combined loading about the z direction at the section containing K. Enter M, as a positive value if the
moment vector is in the direction of the positive x axis. If it's in the opposite direction, enter Mx as a negative value. Similarly,
enter M, as a positive value if the moment vector is in the direction of the positive z axis.
Answers:
Mx =
i
! kN-m
M2 =
! kN-m
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Transcribed Image Text:Part 2 Incorrectzdirectionydirection xdirection K.Combine My. Note that x. Only xdirectionz, M,is positive. See the produces and calculations of equivalent and the produce at the the moment both the The force in moments section components components force in a force in the about containing due to these produce a the moment moments for the negative the two forces negative negative about various combined loading cases in the examples in negative to moment determine about Section 15.4. Calculate M, the moment due to the combined loading about the x direction at the section containing K. Also, calculate M, the moment due to the combined loading about the z direction at the section containing K. Enter M, as a positive value if the moment vector is in the direction of the positive x axis. If it's in the opposite direction, enter Mx as a negative value. Similarly, enter M, as a positive value if the moment vector is in the direction of the positive z axis. Answers: Mx = i ! kN-m M2 = ! kN-m eTextbook and Media Save for Later Attempts: 2 of 5 used Submit Answer
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ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning