Two Linked Genes: P1 P2 Genotype Phenotype: Red, shrunken kernel SS White, Plum kernel F1 RISA Red, plum kernel Testeross Genotype: Phenotype: White.shrunken kernel Red, plump Red, shrunken 3433 White, plump 3329 White, shrunken 133 118 a) State your hypothesis ( b) Test your hypothesis: Phenotypic Class Expected Deviation Observed D2 X2=D2 / E Frequency (0) Frequency (E) (D = 0-E) 1 2 3 n = X2com= c) State your conclusion: d) Compute for the linkage value. Show your solution. e) Make a linkage map.

Two Linked Genes: P1 P2 Genotype Phenotype: Red, shrunken kernel SS White, Plum kernel F1 RISA Red, plum kernel Testeross Genotype: Phenotype: White.shrunken kernel Red, plump Red, shrunken 3433 White, plump 3329 White, shrunken 133 118 a) State your hypothesis ( b) Test your hypothesis: Phenotypic Class Expected Deviation Observed D2 X2=D2 / E Frequency (0) Frequency (E) (D = 0-E) 1 2 3 n = X2com= c) State your conclusion: d) Compute for the linkage value. Show your solution. e) Make a linkage map.

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 9QP: Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic...

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Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?
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Consider the following scenario: A man without freckles (freckles are a dominant trait, determined by the dominant allele “F”) is a carrier of cystic fibrosis (recall that CF is a recessive trait, determined by the recessive allele "a"), mates with a woman whose genotype is heterozygous for freckles and is also a carrier of CF. Assume the two genes in question are in different chromosomes and, therefore, assort independently. Complete the following Punnett square to generate the offspring probabilities from this couple, by entering the genotypes of the parents, the gametes, and the offspring for the two traits described above. (4) Father’s genotype ffAa Mother’s genotypeFfAa ● Sperm: fA ● Sperm: fa ● Sperm: fA ● Sperm: fa ● Egg: FA ● Egg: fA ● Egg: Fa ● Egg: fa What is the probability for this couple to have a child with freckles? What is the…
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You discover a new X-linked mutation for antenna shape in Drosophila (fruit flies) which produces long antennae. You call this new allele long (XL2), and discover it is incompletely dominant with the short antennae allele (XL1), meaning that heterozygotes have antennae that are intermediate in length. In your laboratory population, 9% of the males have long antennae. Assuming your population is in Hardy-Weinberg equilibrium, what proportion of females would you expect to have intermediate antennae? Answer choices: 0.50 0.90 0.83 0.0081 0.16
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TOPIC : Genetics Example's for Question GENE = Hair Color ALLELE = Straight, Curly DOMINANCE = BB RECESSIVE = bb GENOTYPE = BB, Bb, bb PHENOTYPE = Blue, Black HOMOZYGOTE = BB (Blue eye), bb (Black eye) HETEROZYGOTE = Bb (Blue eye) MONOHYBRID = Aa DIHYBRID = AaBb TRIHYBRID = AaBbCc POLIHYBRID = AaBbCcDd MENDELLIAN GENETICS = Hair Color NON MENDELLIA = Blood Type QUESTIONS: Give Example of the following fo differentiate, DO NOT GIVE THE MEANING! (Follow the instructions above!) 1. MONOHYBRID CROSS = ? DIHYBRID CROSS = ? 2. BACK CROSS = ? TEST CROSS = ?
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Corn and Mendelian Genetics Red Smooth Red Wrinkled Yellow smooth yellowwrinkled #Expected 25 25 25 25 #observed 29.6 53.4 7.2 9.8 X2 value 0.85 32.26 12.67 9.24 The data above is from genetic tracking two traits inherited in Corn. Use the X2 values provided to find the sum of the X2 for this stimulation. Round your answer to the nearest tenth. Mendelian genetics (Probability value and degree of freedom) Red Smooth. Red Wrinkled. Yellow smooth yellowwrinkled #Expected. 25 25 25 25 #observed. 29.6 53.4 7.2 9.8 X2 value. 0.85 32.26 12.67 9.24 The data above is from genetic tracking two traits inherited in Corn. Based on the data above , you can see that the difference between the expected and predicted outcomes is -- (a) significant or (b) not significant? the predicted is…