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- An insurance investigator has observed that people with some astrological signs tend to be safer drivers than people with other signs. Using insurance records, the investigator classified 150 people according to their astrological signs and whether or not they were involved in a car accident during the previous 12 months. Do the following data indicate a significant relationship between sign and accidents? Test with a = .05. Libra Leo Gemini Accident 7 4 19 No Accident 73 46 1Which of these four forecasts seems to have the most bias? A. (6,4,3,2) B. 3-period moving average C. Alpha = .3D. Simple moving averageQuestion Two A Deputy Registrar at a certainty university conducted a Chi-Square test of association to establish whether or not employee grade and level of absenteeism were associated. Table 2 below shows part of the results which were obtained. Table 2: Cross tabulation of employee grade and level of absenteeism Contingency Tables Grade LAbsence 1 2 3 Total low Observed 8 1 0 9 Expected 2.90 3.48 2.61 9.00 high Observed 2 11 9 22 Expected 7.10 8.52 6.39 22.00 Total Observed 10 12 9 31 Expected 10.00 12.00 9.00 31.00 2.1 State the appropriate measurement scales for the variables. 2.2 State the null and alternative hypotheses. 2.3 Calculate the expected frequency corresponding to a Grade 3 academic with a high level of absenteeism. 2.4 Find the Chi-Square critical value and test…
- Question 5For each of the following tobs values, determine the highest level of significance associated with the decision taken. tobs df Decision (i) 4.000 17 Reject Ha for a two-tailed test (ii) 1.200 120 Reject Ha for a one-tailed test (iii) -2.660 16 Reject Ha for both one-tailed and two-tailed test (iv) -1.586 60 Reject Ha for a one-tailed testQUESTION 8 Rocky Mountain National Park is a popular park for outdoor recreation activities in Colorado. According to U.S. National Park Service statistics, 46.7% of visitors to Rocky Mountain National Park in 2018 entered through the Beaver Meadows park entrance, 24.3% of visitors entered through the Fall River park entrance, 6.3% of visitors entered through the Grand Lake park entrance, and 22.7% of visitors had no recorded point of entry to the park.† Consider a random sample of 175 Rocky Mountain National Park visitors. Use the normal approximation of the binomial distribution to answer the following questions. (Round your answers to four decimal places.) (a) What is the probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance? (b) What is the probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance? (c) What is the probability that fewer than 12 visitors had a…A car dealer wishes to learn whether they can predict customers preferred car make typebased on suburb so that they could distribute their mail advertising more effectively. Thetable below shows the number of people in a random sample of 245 and their current cars.
- Question 12** The following table lists the approximate number of adults (18+) who are obese (BMI ≥ 25) in North America in 2014 by country and gender. Female Obese Male Obese Female Not Obese Male Not Obese Canada 11 M 12 M 7 M 6 M Mexico 40 M 37 M 21 M 22 M U.S.A. 101 M 113 M 61 M 44 M (adapted from http://apps.who.int/gho/data/node.main.A897A?lang=en) Based on this data, what is the probability that a randomly selected male in North America will be obese? Answer in decimal form. Round to 3 decimal places as needed. Your Answer:Question 5.4 D,E,F,G,H,I with bell curve drawingQuestion 4 a The researcher is concerned that older persons may not be knowledgeable of the COFLU-20. Assuch, he is interested in investigating the association between the age of the respondents and theirknowledge level. Table 2 below shows the knowledge level of respondents, by age group.Table 2Age Group Knowledge Level TotalPoor Satisfactory Good18 - 25 33 16 13 6226 - 34 30 18 12 6035 - 44 29 14 12 5545 - 54 36 16 18 7055 - 75 17 14 22 53Total 145 78 77 300 Conduct a test, at the 5% level of significance, to determine whether the data provided sufficientevidence to conclude that an association exists between age group and knowledge level. (i) State the hypotheses to be tested:H0:H1: Calculate:(ii) state the degrees of freedom for this test (iii) the p-value for this test, given that the chi-square test statistic, x2, is 11.029. (iv) state the conclusion for the test. Give reason for your answer.
- QUESTION 4(a) The researcher is concerned that older persons may not be knowledgeable of the COFLU-20. Assuch, he is interested in investigating the association between the age of the respondents and theirknowledge level. Table 2 below shows the knowledge level of respondents, by age group.Table 2Age Group Knowledge Level TotalPoor Satisfactory Good18 - 25 33 16 13 6226 - 34 30 18 12 6035 - 44 29 14 12 5545 - 54 36 16 18 7055 - 75 17 14 22 53Total 145 78 77 300Conduct a test, at the 5% level of significance, to determine whether the data provided sufficientevidence to conclude that an association exists between age group and knowledge level.(i) State the hypotheses to be tested:H0:H1: [Calculate:(ii) state the degrees of freedom for this test (iii) the p-value for this test, given that the chi-square test statistic, 2, is 11.029.(iv) state the conclusion for the test. Give reason for your answer.continueQUESTION 4(a) The researcher is concerned that older persons may not be knowledgeable of the COFLU-20. Assuch, he is interested in investigating the association between the age of the respondents and theirknowledge level. Table 2 below shows the knowledge level of respondents, by age group.Table 2Age Group Knowledge Level TotalPoor Satisfactory Good18 - 25 33 16 13 6226 - 34 30 18 12 6035 - 44 29 14 12 5545 - 54 36 16 18 7055 - 75 17 14 22 53Total 145 78 77 300Conduct a test, at the 5% level of significance, to determine whether the data provided sufficientevidence to conclude that an association exists between age group and knowledge level.(i) State the hypotheses to be tested:H0:H1: Calculate:(ii) state the degrees of freedom for this test (iii) the p-value for this test, given that the chi-square test statistic, 2, is 11.029.(iv) state the conclusion for the test. Give reason for your answer.for each pair in question 9, which z-score has the higher frequency?