
Using Java implementations presented in the algorithms below.Practice Mergesort
Algorithm:
void mergesort(E[] A, E[] temp, int l, int r) { int i, j, k, mid = (l+r)/2; if (l == r) return; // List has one element if ((mid-l) >= THRESHOLD) mergesort(A, temp, l, mid); else inssort(A, l, mid-l+1); if ((r-mid) > THRESHOLD) mergesort(A, temp, mid+1, r); else inssort(A, mid+1, r-mid); // Do merge. First, copy 2 halves to temp. for (i=l; i<=mid; i++) temp[i] = A[i]; for (j=1; j<=r-mid; j++) temp[r-j+1] = A[j+mid]; // Merge sublists back to array for (i=l,j=r,k=l; k<=r; k++) if (temp[i].compareTo(temp[j])<0) A[k] = temp[i++]; else A[k] = temp[j--];}

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Mergesort Implementation
static <E extends Comparable<? super E>>
void mergesort(E[] A, E[] temp, int l, int r) {
int mid = (1+r)/2;
if (1 =
mergesort(A, temp, l, mid);
mergesort (A, temp, mid+1, r);
for (int i=i; i<=r; i++)' // Copy subarray
temp[i] = A[i];
// Do the merge operation back to A
int il
r) return;
1; int i2 = mid + 1;
for (int curr=l; curr<=r; curr++) {
if (il
A[curr] =
else if (i2 > r) ¯// Right sublist exhausted
A[curr] = temp[il++] ;
else if (temp[il].compareTo (temp[i2])<0)
A[curr] = temp[il++];
else A[curr] = temp[i2++] ;
}
}
mid+1) // Left sublist exhausted
temp[i2++] ;](https://content.bartleby.com/qna-images/question/33367630-baef-4794-a3c7-3f7d1dfa9a18/613037f2-d94a-412f-bc2c-4b9a33f6c636/8iumz3r_thumbnail.png)

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