Virtual Lab Questions 4.00 ppm P 0.82 a. Compare the magnetic character, bond lengths, bond orders, bond dissociation energies, and Urine sample 0.625 relative ionization energies for N2, N2", and N22, using the Molecular Orbital Theory. b. For the molecule selenium tetrafluoride, SeF4, provide a Lewis structure and the hybridization of the central atom. Sketch the species, showing all bond types (identical to that shown in lectures, such as o(1s, sp3)) and bond angles. Name the geometry about the central atom. 3.

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter20: Molecular Mass Spectrometry
Section: Chapter Questions
Problem 20.4QAP
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Virtual Lab Question: A solution of 0.0040 M copper dithizone transmits 66 % of the lisht
1.
particular wavelength in a cell of 1.5 cm thickness. What is the absorbance? What is the mela
absorptivity? What is the concentration of a copper dithizone solution that transmits 20 % under the
same conditions?
Virtual Lab Question: Phosphorus in urine can be determined by treating with molybdenum (VI) and
then reducing the phosphomolybdo complex with aminonaphtholsulfonic acid to give the
characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270 mL of urine
in 24 hours and the pH of the urine was 6.5. A 1.00 mL aliquot of the urine was treated with
molybdate reagent and aminonaphtholsulfonic acid and was diluted to a volume of 50.0 ml
A series of phosphate standards were similarly treated. The absorbance of the solutions at 690 nm.
measured against a blank, were as follows:
Solution
Absorbance
a. Calculate the number of grams of phosphorus
excreted per day.
1.00ppm P
0.205
b. Calculate the phosphorus concentration in the urine
2.00 ppm P
0.41
as millimoles per liter.
3.00 ppm P
0.615
3.
Virtual Lab Questions
a. Compare the magnetic character, bond lengths,
4.00 ppm P
0.82
bond orders, bond dissociation energies, and
Urine sample
0.625
relative ionization energies for N2, N2", and N2²",
using the Molecular Orbital Theory.
b. For the molecule selenium tetrafluoride, SeF4, provide a Lewis structure and the hybridization
of the central atom. Sketch the species, showing all bond types (identical to that shown in
lectures, such as o(1s, sp3)) and bond angles. Name the geometry about the central atom.
9(D) - 7
Transcribed Image Text:2. Virtual Lab Question: A solution of 0.0040 M copper dithizone transmits 66 % of the lisht 1. particular wavelength in a cell of 1.5 cm thickness. What is the absorbance? What is the mela absorptivity? What is the concentration of a copper dithizone solution that transmits 20 % under the same conditions? Virtual Lab Question: Phosphorus in urine can be determined by treating with molybdenum (VI) and then reducing the phosphomolybdo complex with aminonaphtholsulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270 mL of urine in 24 hours and the pH of the urine was 6.5. A 1.00 mL aliquot of the urine was treated with molybdate reagent and aminonaphtholsulfonic acid and was diluted to a volume of 50.0 ml A series of phosphate standards were similarly treated. The absorbance of the solutions at 690 nm. measured against a blank, were as follows: Solution Absorbance a. Calculate the number of grams of phosphorus excreted per day. 1.00ppm P 0.205 b. Calculate the phosphorus concentration in the urine 2.00 ppm P 0.41 as millimoles per liter. 3.00 ppm P 0.615 3. Virtual Lab Questions a. Compare the magnetic character, bond lengths, 4.00 ppm P 0.82 bond orders, bond dissociation energies, and Urine sample 0.625 relative ionization energies for N2, N2", and N2²", using the Molecular Orbital Theory. b. For the molecule selenium tetrafluoride, SeF4, provide a Lewis structure and the hybridization of the central atom. Sketch the species, showing all bond types (identical to that shown in lectures, such as o(1s, sp3)) and bond angles. Name the geometry about the central atom. 9(D) - 7
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