What information can be obtained from DIS80 primer Blast ? A Respect length and number in alleles of a single - locus VNTR B Mitochondrial haplogroups with stubby fingers and curly hair C Investigational New Drug targets for diabetes and obesity D One million independent loci for Alu element in the human genome E Disease- associated

What information can be obtained from DIS80 primer Blast ? A Respect length and number in alleles of a single - locus VNTR B Mitochondrial haplogroups with stubby fingers and curly hair C Investigational New Drug targets for diabetes and obesity D One million independent loci for Alu element in the human genome E Disease- associated

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Description: What information can be obtained from DIS80 primer Blast ?A Respect length and number in alleles of a single - locus VNTR B Mitochondrial haplogroups with stubby fingers and curly hairC Investigational New Drug targets for diabetes and obesity D One

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter11: Genome Alterations: Mutation And Epigenetics

Section: Chapter Questions

Problem 2QP: Achondroplasia is an autosomal dominant form of dwarfism caused by a single gene mutation. Calculate...

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Select all that apply: A SNP (single nucleotide polymorphism) is similar to an STR (short tandem repeat) in that: a) an individual can have many different copies of specific SNP or STR b) they both cause diseases c)they are sequences that have many possible variants d) an individual has one copy of this region of the genome from each parent.
ISSR is generally a dominant STS DNA marker. Nonetheless, with validated experimental evidence (e.g. laboratory and population genetics data), the marker can be used in codominance marker genotyping. Briefly explain each case below: a) Codominant marker targets specific locus and reveals allelic variations in that locus among DNA samples. b) Dominant marker: primers can complement other repeat sequences or in multiple loci thereby non-specificity in sampled genomes.
. Discuss how Genome-wide association studies (GWAS) can be used to identify genetic risk loci for (a) diseases with complex inheritance and (b) pharmacogenomic genotype-phenotype associations. Draw on specific examples and experimental evidence in your discussion.
DNA from 100 unrelated individuals from one population of Chinook salmon were amplified at a single microsatellite locus, and run on an agarose gel. The results from gel electrophoresis shows three different fragment lengths (i.e. alleles/band positions) corresponding to 3 alleles; Allele F (250bp), Allele R (180bp), and Allele Y (100bp). The numbers at the top of each lane is the number of fish observed with that particular genotype or banding pattern in the population. Note that a single band means a homozygote for that allele (band size). a) Calculate the allele frequency for Allele Y. (b) Calculate the genotype frequencies for the following genotypes: FF, FR, and RY. (c) What is the expected number of Chinook salmon with homozygous genotype for allele Y in the study population? (d)What is the name of the statistical test that you could conduct to test whether this population of Chinook salmon is in Hardy Weinberg Equilibrium
Comparing SNPs to STR markers, which of the following are true? Select one: a. SNP loci generally have more alleles than STR loci. b. SNP loci could not be used for forensic CODIS DNA profiling. c. SNPs are not the same as microsatellite DNA. d. There are many more STR loci in the human genome than SNP markers.
Answer the following MCQs: 1:This database is most likely to have data about gene expression. GenBank BLAST dbEST RefSeq PDB 2: Dot matris noise reduction: window size is 7 by 7 and mismatch is 2. What is the minimal number of matches in this window that allows us to place the dot? 2 3 1 5 4 3: Find the optimal global alignment of two DNA sequences _ACAAC and AC. Match = 2, mismatch =0, gap opening =-3, gap extention=-1. What is the total score of alignment? 2 -1 0 -3 1
A method for detecting methylated CpGs involvesthe use of a chemical called bisulfite, which convertscytosine to uracil but leaves methylated cytosine untouched. You want to know whether a particularCpG dinucleotide at one location in the genome ismethylated on one or both strands in a tissue sample.The genomic sequence containing this CpG is:5’...TCCATCGCTGCA…3’. You take genomicDNA from the sample tissue, treat it exhaustivelywith bisulfite, and then use flanking primers toPCR-amplify the region including this CpGdinucleotide. You then want to Sanger sequence(see Fig. 9.7) the amplified PCR product. a. After you treat genomic DNA with bisulfite, the twoDNA strands will melt into single strands. Why?b. Your answer to part (a) introduces a potential complication, because if you do not account for this result of bisulfite treatment, the PCR primers willnot amplify the DNA. What special considerationswould be necessary when you design your PCRprimers for this experiment? Could one pair…
b) Mr. Jason has received an identification card regarding his complete genome. (1) biotechnology tool to develop a complete genome data. Based on answer b (i). justify the advantages and disadvantages of having a complete genotype card?
Briefly explain how Genome Wide Association Studies (GWAS) are done. Then, using this example of a Manhattan Plot explain what each of the X-axis and the Y-axis signifies in a GWAS.
RELPs: A. are the same length for mutant and normal beta-globin alleles. b. determine the sequence of bases in a DNA fragment. c. have short, palindromic sequences of DNA in the middle. D. are used as vectors. e. are produced by reaction with restriction enzymes and are detected with PCR and gel electrophoresis.
Researchers in search of loci in the human genome that arelikely to contribute to the constellation of factors leading tohypertension have compared candidate loci in humans and rats[Stoll, M., et al. (2000). New Target Regions for Human Hypertensionvia Comparative Genomics. Genome Res. 10:473–482].Through this research, they identified 26 chromosomal regionsthat they consider likely to contain hypertension genes. Howcan comparative genomics aid in the identification of genesresponsible for such a complex human disease? The researchersstate that comparisons of rat and human candidate loci tothose in the mouse may help validate their studies. Why mightthis be so?
e. four-base, not overlapping4. An example of a portion of the T4 rIIB gene in whichCrick and Brenner had recombined one + and one −mutation is shown here. (The RNA-like strand of theDNA is shown.)wild type 5′ AAA AGT CCA TCA CTT AAT GCC 3′mutant 5′ AAA GTC CAT CAC TTA ATG GCC 3′a. Where are the + and − mutations in the mutant DNA?b. The double mutant produces wild-type plaques.What alterations in amino acids occurred in thisdouble mutant?c. How can you explain the fact that amino acids aredifferent in the double mutant than in the wild-typesequence, yet the phage has a wild-type phenotype?