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A sample of raw ground beef initially contained 25 E. Coli bacteria. After six hours, there are 102 400 cells in the sample. What is the growth rate of the E. coli population? Show all work. Express your answer using scientific notation in the form of xyz 10 d #bacteria/hr.
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- A species of bacteria has a doubling time of 24 hours. After incubating the initial population for one week, the final population was 6,400 cells. What was the initial population of that bacteria? Show all work. Equations: Nt = No x 2n Final concentration = (initial concentration)/(total dilution factor) Total dilution factor = (individual dilution factor)# of serial dilutionsthe scientist is studying the effect of water purification tablets on the creek water in her local area. She collected several different 2 L samples from a creek. For each sample, she measured the number of coliform group bacteria colonies in the water initially, and then added a water purification tablet and measured the number of coliform group bacteria colonies over time. She found that the following equation was a good fit to the data: C(t) = 80e−0.05t + 8(t + 1)−0.5.Her model says that C(t) is the number of coliform group bacteria colonies at time t, where t is measured in minutes since the tablet was added to the water. (a) According to this model, how many coliform group bacteria colonies would initially be in a 2 L sample of the water? background information: The quality of drinking water is determined by tests for coliform group bacteria, which are organisms found in soil and in the intestinal tract of warm-blooded animals. Coliform group bacteria are not considered to…The bacterium Dontuplodemeus tocheggus has a generation time of 20 minutes. Starting with one cell in 500 mL of culture medium, how many minutes would it take to reach a cell density of approximately one million cells per mL? Assume all cells remain viable. a. 330 b. 660 c. 380 d. 400 e. 580
- A 10-5 dilution is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 278 colony forming units grow on the plate. How many bacteria are in a single mL of the original culture? Express your answer to two decimal places using scientific notation. In scientific notation 540 would be written as 5.40*10^2. Since only 0.1 mL is put on the plate, this counts as an extra dilution!!! Any time less than 1 mL is transferred, a dilution is being performed. Any time more than 1 mL is transferred, a concentration is being performed. Include the trailing zero so there are two decimal places Canvas expects a single digit before the decimal point. 5.40*10^2 is how Canvas expects 540 to be formatted in scientific notation 54.00*10^1 would be marked wrong. 0.54*10^3 would be marked wrong. A 10-5 dilution is performed on a culture of bacteria in order to perform viable plate counts. From the…In an experiment to calculate the decimal reduction time for an Escherichia coli culture, viable cells were exposed to a constant temperature of 80°C for a set amount of time. After exposure, the remaining number of surviving cells were counted. Based on Table 1, what is the decimal reduction time?Table 1. Decimal Reduction Time for E. coli Heated to 80°C Total time of exposure (minutes): Number of Microbial Cells Present: 0 100 1 80 3 50 4 42 6.5 26 13 10 21 0Which of the following types of bacteria can contaminate water sources in hospitals and also cause pulmonary diseases or infections? Question 9 options: Mycobacterium spp. Hydrobacterium spp. Escherichia coli Shigella spp.
- Calculate the doubling time of a culture of E. coli that is started with 3x105 CFU/mL and grows to 4.6x108 CFU/mL in 3 hours. Be sure to use units in your answer.If the temperature of the incubator were to be increased from 35 to 45°C, how would this affect the bacterial growth curve of E. coli? (optimum temperature 20o-40oC; most human pathogens)Calculate the generation time in a growth experiment in which a medium was inoculated with 5 X 106 cells/mL of E. coli cells and following a 1 hour lag, grew exponentially for 5 hours, after which the population was 5.4 X 109cells/mL
- A slant is inoculated with 100 E.coli cells. The slant is left at room temperature where the generation time is 1 hour. How many E. coli are on the slant in 6 hours? If the slant was initially put in the 37C incubator, with a 20 minute generation time, how many more cells would have grown in the same time period?"James inoculated a species of bacteria into KIA media and realized that it has a yellow butt and a red slant. If this same organism was inoculated on McConkey agar, it will likely result in?" red colonies colorless colonies green colonies blue colonies yellow coloniesIf a culture of E. coli you are tracking grows from 5 x 103 cells/ml to 9 x 107 cells per ml in 4 hours, what is the approximate generation time of your E. coli? how can i slove this step by step a. About 14 minutesb. About 17 minutesc. About 20 minutesd. About 23 minutese. About 30 minutes