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- Which of the following is a spontaneous reaction.? a. Rxn with ΔH =- 10Kj/mol ΔS= -5J/mol T= 300K b. NaCl +H20 -> NaOH + HCl 25C c. H20(l) -> H2O(s) Temp: 25C d. Dissolution of 100g of solid sugar in 100 mL ice tea. Consider following reaction: HgO (s) -> Hg(l) + ½ O2 (g) Delta H = +90.7 kj/mol. What quantity of heat in kj/mol is required to produce one mole HgO? Write your answer without units. Given the following data 2ClF(g) + O2(g) --> Cl2O(g) + F2O (g) Delta H= 167.4 kJ I 2ClF3(g) + 2O2(g) --> Cl2O(g) + 3F2 O (g) Delta H= 341.4 kJ II 2 F2(g) + O2(g) ---> 2F2O (g) Delta H= -43.4 kJ III Calculate the delta H in kJ for below reaction: ClF(g) + F2(g) ---> ClF3(g)1.065g of MgO (Analyte) of 84.74% were treated w/ 50ml of 1.02N H2SO4 (Acidic Titrant), and 48.28 mL of NaOH (Base Titrant) 1.103N concentration MW of analyte: 40Meq of analyte: 0.02NaOH vol: 48.28 Compute for the meq weight consumed by the acidic titrant (g-meq)(9.29 × 105/8)-20.81 = with correct sig figs
- One litre of a saturated aqueous solution of Ag2SO4 (MW = 311.79 g mol- 1) at 25 °C is evaporated to dryness. 4.844 g of Ag2SO4 residue was produced. What is the solubility product (Ksp)?Using the term u of KSP experimental procedure the 6 p.m. As you add 5 ml of .004M AgNo to 5ml of .0025M K2CrO4. Is either of these reagents in excess? If so which one?Sagrm.m.
- C8This is for my reviewer please help me with the step by step solution and answer, thank youThe concentration of Cl– in a 300.0-mL sample of water drawn from a fresh water acquifer suffering from encroachment of sea water, was determined by titrating with 0.0516 M Hg(NO3)2. The sample was acidified and titrated to the diphenylcarbazone end point, requiring 6.18 mL of the titrant. Report the concentration of Cl–in parts per millionA particular saturated solution of PBI2 has [Pb2+] = 5.0 x 10^-3 M and [I-] = 1.3 x 10^-3 M. a) what is tge value of Ksp for PbI2? b) what is [I-] in a saturated solution of PbI2 that has a [Pb2+] = 2.5 x 10^-4M? c) what is [Pb2+] in a saturated solution that has [I-] = 2.5 x 10^-4M?