When modelling a distributed load in the free body diagram for the moment equation, the resultant force acts at the distribution’s___________?

1. Determine the reaction forces exerted by the wall onto the anchors at B and C in the structure shown below. 50 J40 B. 250 kg [ans.: MB = 0; Bx = - 1.23 kN (left); By = 1.03 kN (up); Mc = 0; Cx = 1.23 kN (right); Cy = 1.47KN %3D %3D (up)]

Answer is aroun 2401N , Please don't copy the similar solution. Looking for quick and correct solution in handwritten format only.

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Learning Goal: To use Hooke's law to determine the value of an axial load applied to a rectangular shape and to determine its lateral expansion. The element shown below is subjected to the axial compressive force P, which causes the shape to contract longitudinally in the direction a distance of 8 = 0.720 mm. Let h = 144.5 mm, w = 88.50 mm, and L = 298.0 mm. Assume the element is made from steel that has a modulus of elasticity of E= 200 GPa and a value of Poisson's ratio of v=0.32. ♥ Part A Value of the axial load Determine the value of the axial load P. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) P = Submit P μÀ Value Units ? Part B Lateral expansion in the y direction Determine the lateral expansion in the y direction due to the axial load. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) dy = Submit d₂ = Value Part C - Lateral expansion in the z direction μA Submit…

Solve with a free body diagram. Don't use Artificial intelligence tools , Only Handwritten.

4.3. Assessing Risk of Aneurysm Rupture: Studies suggest that the maximum allowable stress (failure strength) for the wall tissue in an aortic aneurysm is o = 220 kPa, after accounting for factor of safety. A physician wants your expert opinion on the maximum diameter that an aortic aneurysm in a hypertensive patient (BP 200/90 mmHg) could be allowed to grow to before rupture becomes imminent. The wall thickness may be assumed to remain unchanged at t = 1.2 mm. State your answer in millimeters of diameter. INDBER

A) A circular rod with a gage length of 3.6 m and a diameter of 2.3 cm is subjected to an axial load of 51 kN . If the modulus of elasticity is 200 GPa , what is the change in length? B)A circular rod with a length of 4 m and a diameter of 2.4 cm is subjected to an axial load of 61 kN . If the resulting change in length is 3.34 mm , what is the modulus of elasticity? C)A circular rod with a length of 3.7 m and a diameter of 2.7 cm is subjected to an axial load and increases in length by 3.26 mm . The initial portion of the stress-strain curve of the material is given. What is the applied load?

> Next question You can retry this question below A triangular distributed load of max intensity w-490 N/m acts on beam AB. The beam is supported by a pin at A and member CD, which is connected by pins at C and D respectively. Determine the reaction forces at A and C. Enter your answers in Cartesian components. Assume the masses of both beam AB and member CD are negligible. cc 030 BY NC SA 2016 Eric Davishahl Variable Value 6.6 m a b C D 11.88 m 4.95 m Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. The reaction at A is A = -11268.69 N. The reaction at Cis C= 11268.69 N. 20 Submit Question Jump to Answer X2-3923.92 B X2+ -8451.52 H X X

some value P, and the final deflection in the direction of the load is A, the load does work U, =PA on the structure. By conservation of energy, this work is stored in the elastic deformation energy of the structure, U¡ . For a truss, the internal strain energy is the sum of the axial strain energies in all the elements. This gives the equation N²L PA =E 2AE where N is the internal axial force in each member.