Which option indicates, in order, whether the following compounds obey the effective atomic number rule? (27Co, 46Pd, 48Cd, 80Hg) K2 [HgI4], [CdI4] 2-, Co2CO8 (no bridging ligand), [Pd (NH3) 2Cl2] Do not fit, warn, warn, do not fit Do not fit, warn, warn, warn Fits, does not fit, does not fit, does not fit Fits, does not fit, does not fit, does not fit Fits, warn, warn, do not fit

Which option indicates, in order, whether the following compounds obey the effective atomic number rule? (27Co, 46Pd, 48Cd, 80Hg) K2 [HgI4], [CdI4] 2-, Co2CO8 (no bridging ligand), [Pd (NH3) 2Cl2] Do not fit, warn, warn, do not fit Do not fit, warn, warn, warn Fits, does not fit, does not fit, does not fit Fits, does not fit, does not fit, does not fit Fits, warn, warn, do not fit

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter8: Bonding In Transition Metal Compounds And Coordination Complexes

Section: Chapter Questions

Problem 53AP

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Similar questions

Which option indicates, in order, whether the following compounds obey the effective atomic number rule? (27Co, 46Pd, 48Cd, 80Hg) K2 [HgI4], [CdI4] 2-, Co2CO8 (no bridging ligand), [Pd (NH3) 2Cl2] A. does not fit, warn, warn, do not fit B-do not fit, warn, warn, warn C. fits, warn, warn, do not fit D- fits, does not fit, does not fit, does not fit E- fits, does not fit, does not fit, does not fit
Which of the following ligands does not donate 6 electrons when coordinating to a transition metal center? Group of answer choices tropylium (C7H7+) cyclooctadiene (COD) cyclopentadiene (C5H5-) benzene (C6H6)
F3C-M ligand is a pi acceptor/ pi donor or neither?
Cyanide (I) and hydride (II) ions are ligands with high trans-directing powers. Which theoretical model can better explain the trans effect of these ligands? A. I- π bond, II- Ϭ bondB. I- Ϭ bond, II- π bondC. I- polarization, II- Ϭ bondD. I- π bond, II- polarization
Which of the following is most likely to bond to Ni2+ as a ligand? Explain. CH3-CH2-CH3 CH3-SiH2-CH3 CH3-O-CH3 |
Werner prepared two compounds by heating a solution of PtCl₂ with triethyl phosphine, P(C₂H₅)₃, which is an excellent ligand for Pt. The two compounds gave the same analysis: Pt,38.8%; Cl, 14.1%; C, 28.7%; P, 12.4%; and H, 6.02%. Writeformulas, structures, and systematic names for the two isomers
Which of the following ligands cannot coordinate in an η1 fashion? Group of answer choices benzene (C6H6) allyl cyclopentadienyl (Cp-) methyl
Account for any differences in the number of unpaired electrons between [Co(H2O)6](BF4)2and [Co(9S3)2](BF4)2, [Ni(H2O)6](BF4)2 and [Ni(9S3)2](BF4)2, and [Fe(H2O)6](BF4)2 and[Fe(9S3)2](BF4)2. a.Your answer must include a labeled d-orbital splitting diagram for each complexshowing the number of unpaired electrons. b.Which is higher in the spectrochemical series, i.e., gives the largest crystal fieldsplitting, H2O or 9S3? 9S3 = 1,4,7-trithiacyclononane
Draw a Lewis structure for the cyclopentadienyl ligand (C5H5)- and explain why it is more likely to bind it’s aromatic protons to a transition metal center compared to the similar benzene molecule (C6H6).
Ligand Field Stabilization Energy (LFSE) value (units of Δo) for: Zr3+ high-spin Fe3+ strong-field Ru2+ weak-field Cu3+ high-spin V+
From the (hypothetical) values of stability constant below, which complexes are more stable and the strength of the ligands increases
what about this answer ? Is this also correct? Isn't it contradict? " However, the back-donation from the metal center to CO's empty 2π* orbital is less extensive than with NO. This is because CO's 2π* orbital is higher in energy compared to NO's 2π* orbital. In summary, both NO and CO are pi-acceptor ligands due to their empty 2π* orbitals. However, NO is expected to be a stronger pi-acceptor ligand than CO because of the presence of the unpaired electron in its 2π* orbital and the lower energy of this orbital. The stronger pi-acceptor ability of NO can lead to a more stable metal-ligand bond, as well as greater electron density redistribution between the metal center and the ligand." I'm so confused NO is weaker or stronger pi-acceptor ligands