Why is it divided in half? I always thought we just plug it into the found rate. That's what I did with the others, and those were right. What's different?
Why is it divided in half? I always thought we just plug it into the found rate. That's what I did with the others, and those were right. What's different?
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 71QRT
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Why is it divided in half? I always thought we just plug it into the found rate. That's what I did with the others, and those were right. What's different?
![Data for the reaction
2 NO(g) + 02 (g) → 2 NO2(g)
are given (for a particular temperature) in the table.
Concentration (mol/L)
Initial rate
Experiment
[NO]
[02]
(mol NO/L· h)
3.6 х 10
5.2 x 10-3
4.6 × 10–8
1
3.6 x 10-4
1.04 x 10-2
9.2 x 10-8
1.8 x 10-4
1.04 x 10–2
2.3 x 10-8
3
1.8 x 10-4
5.2 x 10-3
4
a What is the rate law for this reaction?
Rate = k[NO][O2]
O Rate = k[NO]²[O2]
O Rate = k[NO]?[O2]?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F01e55177-61b2-4b42-9c0d-56b237a86a25%2F4d6544a4-528c-4384-a525-18df80b43a60%2Fhtwztd7_processed.png&w=3840&q=75)
Transcribed Image Text:Data for the reaction
2 NO(g) + 02 (g) → 2 NO2(g)
are given (for a particular temperature) in the table.
Concentration (mol/L)
Initial rate
Experiment
[NO]
[02]
(mol NO/L· h)
3.6 х 10
5.2 x 10-3
4.6 × 10–8
1
3.6 x 10-4
1.04 x 10-2
9.2 x 10-8
1.8 x 10-4
1.04 x 10–2
2.3 x 10-8
3
1.8 x 10-4
5.2 x 10-3
4
a What is the rate law for this reaction?
Rate = k[NO][O2]
O Rate = k[NO]²[O2]
O Rate = k[NO]?[O2]?
![b Calculate the rate constant.
Rate constant = 65
L?/mol? · h
Calculate the rate constant from the first experiment. Note the initial rates are for the disappearan
ΔΝΟ
1
Rate =
2
1
(4.6 × 10-8 mol/L · h) = 2.3 × 10¬8 mol/L · h
At
Rate
2.3 x 10-8 mol/L · h
k
65 L² /mol? · h
%D
NO] [0,] (2.6 x 10-4 mol/L)* (5.2 x 10-8 mol/L)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F01e55177-61b2-4b42-9c0d-56b237a86a25%2F4d6544a4-528c-4384-a525-18df80b43a60%2Fr6pcvqr_processed.png&w=3840&q=75)
Transcribed Image Text:b Calculate the rate constant.
Rate constant = 65
L?/mol? · h
Calculate the rate constant from the first experiment. Note the initial rates are for the disappearan
ΔΝΟ
1
Rate =
2
1
(4.6 × 10-8 mol/L · h) = 2.3 × 10¬8 mol/L · h
At
Rate
2.3 x 10-8 mol/L · h
k
65 L² /mol? · h
%D
NO] [0,] (2.6 x 10-4 mol/L)* (5.2 x 10-8 mol/L)
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