Write a function clean in Python that when is given a string and returns the string with the leading and trailing space characters removed. Details: you must use while loop(s) you must not use the strip method the space characters are the space ' ' , newline '\n' , and tab '\t' >>> clean(" hello ") 'hello'

The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive.   For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself.     public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1;   if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); }   public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…

Can you use Python programming language to to this question? Thanks

Consider the following line of code: X = new int*[n]; What should the type of x be? O int O int* O int** O int& O None of the above

Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'

Python IDLE: How would I write a function for the problem in the attached image?

Python question please include all steps and screenshot of code. Also please provide a docstring, and comments throughout the code, and test the given examples below. Thanks. Develop function fingerprint() that takes text (as a string) as input and creates andreturns the text “fingerprint” obtained as follows: replace each word in the text by itslength (i.e., the number of letters) and concatenate these numbers.>>> fingerprint('This is a secret message')'42167'>>> fingerprint('This message has a different fingerprint')'4731911'>>> fingerprint('Very Short')'45'

Use a while loop function instead of a for loop sing python