Could you please try to call these functions with input strings having different combinations of lowercase and uppercase letters? Code: def any_lowercase5(s): # Loop through each character in the string s for c in s: # Check if the character is not a lowercase letter using the islower() method if not c.islower(): # If a character is not lowercase, return False return False # If all characters are lowercase, return True return True

In C language / Please don't use (sprint) function. Write a function fact_calc that takes a string output argument and an integer input argument n and returns a string showing the calculation of n!. For example, if the value supplied for n were 6, the string returned would be 6! 5 6 3 5 3 4 3 3 3 2 3 1 5 720 Write a program that repeatedly prompts the user for an integer between 0 and 9, calls fact_calc and outputs the resulting string. If the user inputs an invalid value, the program should display an error message and re-prompt for valid input. Input of the sentinel -1 should cause the input loop to exit. Note: Don't print factorial of -1, or any number that is not between 0 and 9. SAMPLE RUN #4: ./Fact Interactive Session Hide Invisibles Highlight: None Show Highlighted Only Enter·an·integer·between·0·and·9·or·-1·to·quit:5↵ 5!·=·5·x·4·x·3·x·2·x·1·x··=·120↵ Enter·an·integer·between·0·and·9·or·-1·to·quit:6↵ 6!·=·6·x·5·x·4·x·3·x·2·x·1·x··=·720↵…

Please help! There is a bug in my program that causes it to jump to the notfound function before checking the entire substring The program should determine whether the second string is a substring of the first. If it is, then the program should print out the first index in which the second string appears in the first. As an example, if the first string is “Hello World” and the second string is “lo”, then the program should print out 3, i.e. the starting index of “lo” in “Hello World.” If the second string is not contained in the first string, then the program should print out -1. Here is the code:  .datastr1: .space 51 #space for str1 (max50 characters including null terminator)str2: .space 51 #space for str2 (max50 characters incl null terminator)msg1: .asciiz "Please enter the first string: " #prompt user to enter str1msg2: .asciiz "Please enter the second string: " #prompt user to enter str2newline: .asciiz "\n" .text.globl mainmain:    # Print sttr1    li $v0, 4    la $a0, msg1…

Create a function that will test if a string is a valid PIN or not via a regular expression. A valid PIN has: Exactly 4 or 6 characters. Only numeric characters (0-9). • No whitespace. Examples validate("121317") → true validate("1234") → true validate("45135") → false validate("89abc1") → false validate("900876") → true validate(" 4983") false

// Write a function that takes 1 argument, a string. // It returns true if the string is a palindrome (the same forwards and backwards). // It returns false if the string is not a palindrome. const isPalindrome = (string) => { // your code here... // Examples isPalindrome("cat") // returns false //isPalindrome("level") // returns true }

Consider the following line of code: X = new int*[n]; What should the type of x be? O int O int* O int** O int& O None of the above

Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'

Here is a function that is supposed to return True if word (any string) ends with "s" and False otherwise: def ends_with_s(word):if len(word) < 1:return False    return word[-1] == "s" Here is the test function I am using to test ends_with_s: def test_ends_with_s():    assert(ends_with_s("cats")) # option 1    assert(ends_with_s("") is False) # option 2    assert(ends_with_s("apple") is False) # option 3    assert(ends_with_s("S")) # option 4   Rewrite ends_with_s so that the test passes

please code in pythonis_phone_num: This Boolean function takes a string and returns True if it is in the formatddd-ddd-dddd, where d is a digit, False otherwise. Example calls:is_phone_num('123-456-7890') --> Trueis_phone_num('123-4556-7890') --> Falseis_phone_num('(123)456-7890') --> False

Python IDLE: How would I write a function for the problem in the attached image?