Write a program (JAVA PROGRAMMING) that inputs five integers and determines and prints the  number of negative integers entered, number of positive integers entered and the  number of zeros entered. Below is a sample output. In your program, you should test  run your program for 5 different scenarios.

Write a program with total change amount as an integer input, and output the change using the fewest coins, one coin type per line. The coin types are Dollars, Quarters, Dimes, Nickels, and Pennies. Use singular and plural coin names as appropriate, like 1 Penny vs. 2 Pennies.

Statistics are often calculated with varying amounts of input data. Write a program that takes any number of non-negative integers as input, and outputs the average and max. A negative integer ends the input and is not included in the statistics. Ex: When the input is: 15 20 0 5 -1 the output is: 10 20 You can assume that at least one non-negative integer is input.   import java.util.Scanner; public class LabProgram {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);int numValue;int average;int max;int numValues;int numTotal;numTotal = 0;numValues = 0;max = 0;numValue = scnr.nextInt();while (numValue > 0){numTotal = numTotal + numValue;numValues = numValues + 1;numValue = scnr.nextInt();}average = numTotal / numValues;System.out.print(average);while (numValues > max){max = numValues;System.out.print(" " + max);} }} Why is it giving me the wrong output??

Write a program that receives an integer from the user and prints Large if that number is greater than or equal to 100, prints average if that number is between 20 and 100, and prints Small if that number is less than or equal to 20. You can get an input from user and convert it to an integer using a = int(input('Please enter an integer:'))

Write a Java program that: Ask user to enter the last two digits of the Student ID number and store it in a variable of type integer; Use a while loop to print all the positive odd numbers smaller than the inputted number. After the while loop, make a for loop to print all the positive even numbers smaller than the inputted Note: Your answer should have the code as text, as well as a screenshot of the code with the output.  The inputted number should be the last two digits of your Student ID number.  ID is : 190058401

Write a program that takes in four positive integers and outputs the number of odd numbers. (Hint: use the modulo operator to determine if a number is odd) Ex: If the input is: 1 2 3 4 the output is: 2 Below is my code so far and I'm getting back unexpected EOF while parsing. I can't figure out what I'm doing wrong. odd_number=[]number_1=int(input())number_2=int(input())number_3=int(input())number_4=int(input())if number_1%2!=0:    odd_number.append(number_1)else:    passif number_2%2!=0:    odd_number.append(number_2)else:    passif number_3%2!=0:    odd_number.append(number_3)else:    passif number_4%2!=0:    odd_number.append(number_4)else:    passprint(len(odd_number)

Write a program that takes in an integer in the range 11-100 as input. The output is a countdown starting from the integer, and stopping when both output digits are identical. Additionally, output the distance between the starting and ending numbers (ex: 93 - 88 = 5) Note: End with a newline. Ex: If the input is: 93 the output is: 93 92 91 90 89 88 5 Ex: If the input is: 11 the output is: 11 0 Ex: If the input is: 9 or any value not between 11 and 100 (inclusive), the output is: Input must be 11-100 For coding simplicity, follow each output number by a space, even the last one. Use a while loop. Compare the digits; do not write a large if-else for all possible same-digit numbers (11, 22, 33, …, 99), as that approach would be cumbersome for larger ranges. Hint: To practice incremental development, start by writing code that just outputs the countdown until matching digits and submit to get most of the points. Then, update your code to output the distance.

Write a program that outputs all the integers between 100 and 1000 (inclusive), that are divisible by 5 and also 6. (This means start at 100 and go up to 1000, but only output integers that are divisible by both 5 and 6.) Remember what "divisible" means - if a number is divisible by 5, there is no remainder when you divide it by 5. If a number is divisible by 6, there is no remainder when you divide it by 6. In java