x y 23.2 516.8 29.6 -1729.2 37.5 343.1 19.3 3124.3 57.7 1938.3 18.3 -1530.7 20.4 2383.3 30.8 259.6 47.4 -1722.4 29.2 -281.9 12.5 1882.6 7.1 3495.8 54.5 1335.1 32 1372.8 209.5 -17404.2 Use your graphing calculator to determine the correlation coefficient for this data set. Round your answer to the nearest thousandth. r=r=

x y 23.2 516.8 29.6 -1729.2 37.5 343.1 19.3 3124.3 57.7 1938.3 18.3 -1530.7 20.4 2383.3 30.8 259.6 47.4 -1722.4 29.2 -281.9 12.5 1882.6 7.1 3495.8 54.5 1335.1 32 1372.8 209.5 -17404.2 Use your graphing calculator to determine the correlation coefficient for this data set. Round your answer to the nearest thousandth. r=r=

Name: xy23.2516.829.6-1729.237.5343.119.33124.357.71938.318.3-1530.720.42383
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: xy23.2516.829.6-1729.237.5343.119.33124.357.71938.318.3-1530.720.42383.330.8259.647.4-1722.429.2-281.912.51882.67.13495.854.51335.1321372.8209.5-17404.2Use your graphing calculator to determine the correlation coefficient for this data set. Round you

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.6: Summarizing Categorical Data

Problem 34PPS

See similar textbooks

x	y
23.2	516.8
29.6	-1729.2
37.5	343.1
19.3	3124.3
57.7	1938.3
18.3	-1530.7
20.4	2383.3
30.8	259.6
47.4	-1722.4
29.2	-281.9
12.5	1882.6
7.1	3495.8
54.5	1335.1
32	1372.8
209.5	-17404.2

Similar questions

Find the positive geometric mean between 4 and 64.
Date DJIA S&P 500 Day 1 35405.24 4536.54 Day 2 35629.33 4579.38 Day 3 35111.16 4467.44 Day 4 35089.74 4510.53 Day 5 35091.13 4493.87 Day 6 35462.78 4511.54 Day 7 35768.06 4577.18 Day 8 35241.59 4514.08 Day 9 34738.06 4408.64 Day 10 34566.17 4411.67 Day 11 34988.84 4461.07 Day 12 34934.27 4485.01 Day 13 34312.03 4390.26 Day 14 34079.18 4358.87 Day 15 33596.61 4314.76 Day 16 33131.76 4235.50 Day 17 33223.83 4278.70 Day 18 34058.75 4394.65 Day 19 33892.60 4363.94 Day 20 33294.95 4316.26 Day 21 33891.35 4396.54 Day 22 33794.66 4353.49 Day 23 33614.80 4318.87 Day 24 32817.38 4211.09 Day 25 32632.64 4180.70 Day 26 33286.25 4287.88 Day 27 33174.07 4249.52 Day 28 32944.19 4194.31 Day 29 32945.24 4183.11 Day 30 33544.34 4252.45 Day 31 34063.10 4367.86 Day 32 34480.76 4421.67 Day 33 34754.93 4473.12 Day 34 34552.99 4471.18 Day 35 34807.46 4521.61 Day 36 34358.50 4466.24 Day 37 34707.94 4510.16 Day 38 34861.24 4553.06…
Date DJIA S&P 500 January 6 12,360 1,278 January 13 12,422 1,289 January 20 12,720 1,287 January 27 12,660 1,234 February 3 12,862 1,267 February 10 12,801 1,243 February 17 12,950 1,262 February 24 12,983 1,313 March 2 12,978 1,255 March 9 12,922 1,371 March 16 13,233 1,404 March 23 13,081 1,397 March 30 13,212 1,408 April 5 13,060 1,398 April 13 12,850 1,370
Male Female26,801 21,39217,251 25,0384,624 4,47927,801 18,27024,555 10,6637,767 17,11020,536 10,77916,516 19,98425,601 14,05620,948 18,51912,153 17,70311,382 11,30813,138 17,00723,568 25,14217,874 5,616102 17,63120,292 24,5689,701 16,93722,178 15,53116,189 12,88517,664 30,97022,418 6,5195,993 18,3335,899 6,10424,563 10,00311,655 17,88411,600 12,35514,317 20,13011,649 21,96117,427 13,33914,658 35,76910,205 10,68520,063 9,15415,219 11,99611,846 30,61614,723 20,53517,184 16,2678,686 17,89917,833 20,14113,345 14,90014,770 19,1535,386 11,94719,548 16,55313,755 18,12515,959 30,23816,800 38,61218,987 24,75439,299 33,12517,677 25,55947,062 32,94627,391 20,46511,298 5,18615,815 25,02111,590 14,5586,579 15,67619,395 28,954
Calculate the point prevalence for Alzheimer’s disease among individuals 65 years of age or older in a county that has 200,000 individuals who are 65 years of age or older, if 22,223 individuals who are 65 years of age or older have the disease. 0.0111 0.1111 0.8889 0.9889
3.273525429 3.725058267 3.193881287 3.380595777 3.849062312 2.688788698 4.521501366 2.876926464 3.202865171 3.760862809 3.648737967 3.155042169 3.047772295 2.331491399 2.43426651 3.316262576 3.33570391 3.123784316 1.983014564 4.026381813 2.819851735 3.020835161 3.963952045 3.434812572 2.530150764 3.501124236 2.723868073 3.734018756 3.07485433 2.945439985 2.963046282 3.301251136 3.806637216 2.495620331 2.99022362 2.548798319 2.849586988 3.554039618 3.565046584 3.383944772 2.895875003 3.96006813 3.744978387 4.034873151 3.394484477 4.637022161 3.085000083 3.945715143 2.590540526 3.593019815 Data from sheet 5
Suppose we want to estimate the annual high temperatures of the hottest major cities in the United States. Below is data from 12 cities with the average annual temperature taken from 1971 to 2000 City Temperature (Fahrenheit) Phoenix, Arizona 87.2 Miami, Florida 84.3 Orlando, Florida 82.8 Riverside, California 80.9 Austin, Texas 79.8 Houston, Texas 79.7 San Antonio, Texas 80.3 Las Vegas, Nevada 80.1 Jacksonville, Florida 79.3 New Orleans, Louisiana 78.2 Tampa, Florida 81.7 Los Angeles, California 75.2 What's the population for this study? What's the sample for this study?
The following table shows the approximate number of wireless telephone subscriptions in a certain country for recent years.
4. The number of passengers (in thousands) for the leading U.S. passenger airlines in 2004 is indicated below. 91,570 86,755 81,066 70,786 55,373 42,400 40,551 21,119 16,280 14,869 13,659 13,417 13,170 12,632 11,731 10,420 10,024 9,122 7,041 6,954 6,406 6,362 5,930 5,585 5,427• Use the data to construct a grouped frequency distribution and a cumulative frequency distribution with a reasonable number of classes and comment on the shape of the distribution using graph.
A manufacturer of exercise equipment knows that 15% of their products aredefective. They also know that only 35% of their customers will actually use the equipment in the first year after it is purchased. If there is a one-year warranty on the equipment, what proportion of the customers will actually make a valid warranty claim?
Regular Coke Diet Coke Regular Pepsi Diet Pepsi 0.8192 0.7773 0.8258 0.7925 0.8150 0.7758 0.8156 0.7868 0.8163 0.7896 0.8211 0.7846 0.8211 0.7868 0.8170 0.7938 0.8181 0.7844 0.8216 0.7861 0.8247 0.7861 0.8302 0.7844 0.8062 0.7806 0.8192 0.7795 0.8128 0.7830 0.8192 0.7883 0.8172 0.7852 0.8271 0.7879 0.8110 0.7879 0.8251 0.7850 0.8251 0.7881 0.8227 0.7899 0.8264 0.7826 0.8256 0.7877 0.7901 0.7923 0.8139 0.7852 0.8244 0.7852 0.8260 0.7756 0.8073 0.7872 0.8227 0.7837 0.8079 0.7813 0.8388 0.7879 0.8044 0.7885 0.8260 0.7839 0.8170 0.7760 0.8317 0.7817 0.8161 0.7822 0.8247 0.7822 0.8194 0.7874 0.8200 0.7742 0.8189 0.7822 0.8172 0.7833 0.8194 0.7839 0.8227 0.7835 0.8176 0.7802 0.8244 0.7855 0.8284 0.7892 0.8244 0.7859 0.8165 0.7874 0.8319 0.7775 0.8143 0.7907 0.8247 0.7833 0.8229 0.7771 0.8214 0.7835 0.8150 0.7870 0.8291 0.7826 0.8152 0.7833 0.8227 0.7815 0.8244 0.7822 0.8211 0.7791 0.8207 0.7837…
Petal length (in cm) of Iris virginica: x1; n1 = 36 5.0 5.6 6.1 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.7 5.3 5.3 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.6 1.6 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.7 Let ?1 be the population mean for x1 and let ?2 be the population mean for x2. Find a 99% confidence interval for ?1 − ?2. (Round your answers to two decimal places.) lower limit: upper limit: Which distribution did you use? Why? A) The standard normal distribution was used because ?1 and ?2 are unknown. B) The Student's t-distribution was used because ?1 and ?2 are known. C) The Student's t-distribution was used because ?1 and ?2 are unknown. D) The standard normal distribution was used because ?1 and ?2 are known. Do you need information about the petal length…