You generate a scatter plot using Excel. You then have Excel plot the trend line and report the equation and the r value. The regression equation is reported as y = 69.87x +54.78 and the r 0.3721. What is the correlation coefficient for this data set?

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as -36.51x+76.99 and r = -0.437. What proportion of the variation in y can be explained by the linear regression equation found above? % Report answer as a percentage accurate to one decimal place. Submit Question

You generate a scatter plot using Excel. You then have Excel plot the trend line and report the equation and the r2r2 value. The regression equation is reported asy=−38.54x+27.71y=-38.54x+27.71and the r2=0.36r2=0.36.What is the correlation coefficient for this data set?r =

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as y = – 17.88x + 41.39 and the r = - 0.405. What proportion of the variation in y can be explained by the variation in the values of x? r2 = Report answer as a percentage accurate to one decimal place.

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as y = -10.91x + 44.13 and r = -0.92. What proportion of the variation in y can be explained by the linear regression equation found above? % Report answer as a percentage accurate to one decimal place.

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as Y = – 17.88x + 41.39 and the r 0.09. What percentage of the variation in y can be explained by the variation in the values of x? r2 = (Report exact answer, and do not enter the % sign)

The data show the chest size and weight of several bears. Find the regression​ equation, letting chest size be the independent​ (x) variable. Then find the best predicted weight of a bear with a chest size of 58 inches. Is the result close to the actual weight of 572 ​pounds? Use a significance level of 0.05.   Chest size​ (inches) 46 57 53 41 40 40   Weight​ (pounds) 384 580 542 358 306 320   LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r. What is the regression​ equation?   y=nothing+nothingx ​ (Round to one decimal place as​ needed.)

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as y = - 74.51a + 28.98 and the r = - 0.339. What proportion of the variation in y can be explained by the variation in the values of x? r2 = Report answer as a percentage accurate to one decimal place.

Using your favorite statistics software package, you generate a scatter plot with a regression equ correlation coefficient. The regression equation is reported as y = -11.24x +34.27 and the r = -0.47. What proportion of the variation in y can be explained by the variation in the values of x? r² = % Report answer as a percentage accurate to one decimal place. Submit Question

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as 90.18x + 67.52 and the r = -0.345. What proportion of the variation in y can be explained by the variation in the values of x? s2 = Report answer as a percentage accurate to one decimal place.