Chapter 0, Problem 43PR

To determine

The perimeter and area of the given triangle.

Answer to Problem 43PR

  $\begin{array}{l}A={\text{96 cm}}^2\\ P=48\text{ cm}\end{array}$

Explanation of Solution

Given:

Base $b=16$ cm Perpendicular $p=12$ cm

Hypotenuse $h=20$ cm

Formula used:

Area of triangle

  $A=\frac{1}{2}\left(b\times p\right)$

Perimeter of triangle

  $P=b+h+p$

Where,

  $b=$ Base

  $p=$ Perpendicular

  $h=$ Hypotenuse

Calculation:

Area of triangle

  $\begin{array}{l}A=\frac{1}{2}\left(b\times p\right)\\ A=\frac{1}{2}\left(16\times 12\right)\\ A=\frac{192}{2}\\ A=96{\text{ cm}}^2\end{array}$

Perimeter of the triangle

  $\begin{array}{l}P=b+p+h\\ P=16+12+20\\ P=48\text{ cm}\end{array}$

Conclusion:

Hence, the perimeter of triangle is

  $48\text{ cm}$ and area of the triangle is ${\text{96 cm}}^2$ .