Chapter 0, Problem 47PR

To determine

The circumference and area of the given circle.

Answer to Problem 47PR

  $\begin{array}{l}A=12.6{\text{ m}}^2\\ C=12.6\text{ m}\end{array}$

Explanation of Solution

Given:

Radius $r=2$ m

Formula used:

Area of circle,

  $A=\pi r^2$

Circumference of circle,

  $C=2\pi r$

Where,

  $r=$ Radius

Calculation:

Area of circle,

  $\begin{array}{l}A=\pi r^2\\ A=3.14\times {\left(2\right)}^2\\ A=12.56{\text{ m}}^2\end{array}$

Nearest tenth is 12.6, so the area of circle is $\text{12}{\text{.6 m}}^2$ .

Circumference of circle,

  $\begin{array}{l}C=2\pi r\\ C=2\times 3.14\times 2\\ C=12.56\text{ m}\end{array}$

Nearest tenth is 12.6, so the circumference of circle is $\text{12}\text{.6 m}$ .

Conclusion:

Hence, the circumference of circle is $\text{12}\text{.6 m}$ .and area of circle is $\text{12}{\text{.6 m}}^2$ .