Explanation Given information: The equation, 6 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 4 − 8 x ( x 2 + 1 ) 3 ( x 2 + 2 ) 3 ( x 2 + 2 ) 8 = 0 . Formula used: Zero product property, If a product of two number is zero, one of the two must be zero. Condition to solve an equation of the form P Q = 0 , If P Q = 0 , then P = 0 . Calculation: Consider the expression, 6 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 4 − 8 x ( x 2 + 1 ) 3 ( x 2 + 2 ) 3 ( x 2 + 2 ) 8 = 0 As the above equation is in P Q = 0 form. Therefore, the equation will be 6 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 4 − 8 x ( x 2 + 1 ) 3 ( x 2 + 2 ) 3 = 0 . As both the term contains the term 2 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 3 . Thus, the common factor is 2 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 3 . Now, factor out the common factor and simplify as below, 6 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 4 − 8 x ( x 2 + 1 ) 3 ( x 2 + 2 ) 3 = 0 2 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 3 ( 3 ( x 2 + 2 ) − 4 ( x 2 + 1 ) ) = 0 2 x ( x 2 + 1 ) 2 ( <

WebAssign Printed Access Card for Waner/Costenoble's Applied Calculus, 7th Edition, Single-Term

7th Edition

ISBN: 9781337652742

Author: Stefan Waner, Steven Costenoble

Publisher: Cengage Learning

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Chapter 0.6, Problem 16E

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To calculate: The solution of the equation 6x(x2+1)2(x2+2)4−8x(x2+1)3(x2+2)3(x2+2)8=0.

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Chapter 0.6, Problem 15E

Chapter 0.6, Problem 17E

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Chapter 0 Solutions

WebAssign Printed Access Card for Waner/Costenoble's Applied Calculus, 7th Edition, Single-Term

Ch. 0.1 - Prob. 1E Ch. 0.1 - Prob. 2E Ch. 0.1 - Prob. 3E Ch. 0.1 - Prob. 4E Ch. 0.1 - Prob. 5E Ch. 0.1 - Prob. 6E Ch. 0.1 - Prob. 7E Ch. 0.1 - Prob. 8E Ch. 0.1 - Prob. 9E Ch. 0.1 - Prob. 10E

Ch. 0.1 - Prob. 11E Ch. 0.1 - Prob. 12E Ch. 0.1 - Prob. 13E Ch. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 15E Ch. 0.1 - Prob. 16E Ch. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 18E Ch. 0.1 - Prob. 19E Ch. 0.1 - Prob. 20E Ch. 0.1 - Prob. 21E Ch. 0.1 - Prob. 22E Ch. 0.1 - Prob. 23E Ch. 0.1 - Prob. 24E Ch. 0.1 - Prob. 25E Ch. 0.1 - Prob. 26E Ch. 0.1 - Prob. 27E Ch. 0.1 - Prob. 28E Ch. 0.1 - Prob. 29E Ch. 0.1 - Prob. 30E Ch. 0.1 - Prob. 31E Ch. 0.1 - Prob. 32E Ch. 0.1 - Prob. 33E Ch. 0.1 - Prob. 34E Ch. 0.1 - Prob. 35E Ch. 0.1 - Prob. 36E Ch. 0.1 - Convert each expression in Exercises 25-50 into...Ch. 0.1 - Prob. 38E Ch. 0.1 - Prob. 39E Ch. 0.1 - Prob. 40E Ch. 0.1 - Prob. 41E Ch. 0.1 - Prob. 42E Ch. 0.1 - Prob. 43E Ch. 0.1 - Prob. 44E Ch. 0.1 - Prob. 45E Ch. 0.1 - Prob. 46E Ch. 0.1 - Prob. 47E Ch. 0.1 - Prob. 48E Ch. 0.1 - Prob. 49E Ch. 0.1 - Prob. 50E Ch. 0.2 - Evaluate the expression sin Exercises 116. 33 Ch. 0.2 - Prob. 2E Ch. 0.2 - Evaluate the expression sin Exercises 116. 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Prob. 12E Ch. 0.5 - Prob. 13E Ch. 0.5 - Prob. 14E Ch. 0.5 - By any method, determine all possible real...Ch. 0.5 - Prob. 16E Ch. 0.5 - Prob. 17E Ch. 0.5 - Prob. 18E Ch. 0.5 - Prob. 19E Ch. 0.5 - Prob. 20E Ch. 0.5 - Prob. 21E Ch. 0.5 - Prob. 22E Ch. 0.5 - Prob. 23E Ch. 0.5 - Prob. 24E Ch. 0.5 - Prob. 25E Ch. 0.5 - Prob. 26E Ch. 0.5 - Prob. 27E Ch. 0.5 - Prob. 28E Ch. 0.5 - Prob. 29E Ch. 0.5 - Prob. 30E Ch. 0.5 - Prob. 31E Ch. 0.5 - Prob. 32E Ch. 0.5 - Prob. 33E Ch. 0.5 - Prob. 34E Ch. 0.5 - Prob. 35E Ch. 0.5 - Prob. 36E Ch. 0.5 - Prob. 37E Ch. 0.5 - Prob. 38E Ch. 0.5 - Prob. 39E Ch. 0.5 - Prob. 40E Ch. 0.5 - Prob. 41E Ch. 0.5 - Prob. 42E Ch. 0.5 - Prob. 43E Ch. 0.5 - Prob. 44E Ch. 0.6 - Solve the equations in Exercises 126. x43x3=0 Ch. 0.6 - Prob. 2E Ch. 0.6 - Prob. 3E Ch. 0.6 - Prob. 4E Ch. 0.6 - Prob. 5E Ch. 0.6 - Prob. 6E Ch. 0.6 - Prob. 7E Ch. 0.6 - Prob. 8E Ch. 0.6 - Prob. 9E Ch. 0.6 - Prob. 10E Ch. 0.6 - Prob. 11E Ch. 0.6 - Prob. 12E Ch. 0.6 - Prob. 13E Ch. 0.6 - Prob. 14E Ch. 0.6 - 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In Exercises 2946,...Ch. 0.8 - Prob. 32E Ch. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Prob. 34E Ch. 0.8 - Prob. 35E Ch. 0.8 - Prob. 36E Ch. 0.8 - Prob. 37E Ch. 0.8 - Prob. 38E Ch. 0.8 - Prob. 39E Ch. 0.8 - Prob. 40E Ch. 0.8 - Prob. 41E Ch. 0.8 - Prob. 42E Ch. 0.8 - Prob. 43E Ch. 0.8 - Prob. 44E Ch. 0.8 - Prob. 45E Ch. 0.8 - Prob. 46E Ch. 0.8 - Prob. 47E Ch. 0.8 - Prob. 48E Ch. 0.8 - Prob. 49E Ch. 0.8 - Prob. 50E Ch. 0.8 - Prob. 51E Ch. 0.8 - Prob. 52E Ch. 0.8 - Prob. 53E Ch. 0.8 - Prob. 54E Ch. 0.8 - Prob. 55E Ch. 0.8 - Prob. 56E

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The solution of the equation 6 x ( x 2 + 1 ) 2 ( x 2 + 2 ) 4 − 8 x ( x 2 + 1 ) 3 ( x 2 + 2 ) 3 ( x 2 + 2 ) 8 = 0 .

Solution Summary: The author explains the formula used to solve an equation of the form PQ=0.

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To calculate: The solution of the equation 6x(x2+1)2(x2+2)4−8x(x2+1)3(x2+2)3(x2+2)8=0.

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Chapter 0 Solutions