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Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248

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Chapter
Section
BuyFindarrow_forward

Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248
Textbook Problem

Solve the equations in Exercises 1–26.

x 4 3 x 3 = 0

To determine

To calculate: The solution of the equation x43x3=0.

Explanation

Given information:

The equation, x43x3=0.

Formula used:

Zero product property:

If a product of two number is zero, one of the two must be zero.

Calculation:

Consider the expression,

x43x3=0

The left side expression is x43x3.

As both the term contains the term x3. Thus, the common factor is x3.

Now, factor out the common factor and simplify as below,

x43x3=x3(x3)

Therefore, the factors of the expression x43x3 are x3(x3)

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