Concept explainers
(a)
To determine: An empirical formula of the given compound X.
Interpretation: An empirical formula of the given compound X is to be stated.
Concept introduction: Empirical formula is the type of chemical formula in which the atoms are present in simple whole number ratios. That means one empirical formula represents one or more chemical formula.
Empirical formula of any compound represents simplest relative whole number ratio of atoms of each element.
Molecular formula of any compound represents actual number of atoms of each element present in one molecule.
(b)
To determine: The molecular formula of the given compound X.
Interpretation: The molecular formula of the given compound X is to be stated.
Concept introduction: Empirical formula of any compound represents simplest relative whole number ratio of atoms of each element.
Molecular formula of any compound represents actual number of atoms of each element present in one molecule.
(c)
To draw: The four complete structural formulas of the given compound.
Interpretation: The four complete structural formulas of the given compound are to be drawn.
Concept introduction: The complete structural formula of the compound is that in which complete arrangement of all the atoms of the compound is given.
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EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
- 2. Name the following compounds: CH3 CH3 CH2 H3C CH CH CH CH3 CH3 I a. CH 3 CH₂ CH 3 CH 3 CH₂ CH CH CH CH3 CH2 CH b. CH 3 CH3 c. H&C CH-CH CH33 H3C-C- Br CH3 -CI d. e. CH3 CH2 I CH-F CH₂ CH2 CH2 CH 3 f. CH 3 CH CH 3 CH2 CH₂ CH CH₂ CH3 'CH CH3 g.arrow_forward1. What is the chemical formula for each of the following compounds? (3 point × 4) a. Octane b. Propane c. Nonane d. Heptane 2. Write the chemical formula, condensed structural formula, and line structure for each of the following compounds (3 points × 4) a. 2-hexene b. 3-octene c. 3-decene d. 1-butynearrow_forwardWhat is the empirocal formula for each compound? a. AL2CL6 b. K2Cr2O7 c. C2H4 d.(NH2)2CNH e. CH3COOHarrow_forward
- A. Classification of Hydrocarbons. H H 6. H-C=C-C-C-H H H 2. H-C-Ċ-H H HHH H-C=C-C=C-H 8. CH CH; CH CH-CH,-CH, CH: CH, CH, CH, 10.arrow_forward7. Name the following compounds. a. H3C- b. H3C- OH H₂ H₂ C-C C H C - CH3 c. H3C-0- -CH3 -CH3 HO- a. b. C. SHO OHarrow_forwardIdentify the functional groups in each molecule.arrow_forward
- CH3 0 H3C-C-C-CH3 ČH3 Type of functional group. n. CH3 0 H;C-C-C-cCH, CH3 IUPAC CH3 0 H,C-C-C-cCH, CH3 Derived Name NH Type of functional group. O. `NH Common Namearrow_forward17. Calculate the percent composition of C6H12O6 Group of answer choices a) 40% C , 53% O , 7 % H b) 25% C, 25% O, 50% H c) 35% C, 48% O, 17% H d) 10% C, 70% O, 20% Harrow_forward1. Name the following molecules. Spelling counts. Br H,C -CH3 CH3 CI a. CH3 b. CI-C-CH,CH,CH с. но H. CH,OHarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning