(a)
The ultimate tensile stress of metal specimen.
Answer to Problem 1.5.1P
Explanation of Solution
Given:
The diameter of metal specimen is
The load at facture is
Concept Used:
Write the equation to calculate the ultimate tensile stress.
Here, ultimate tensile stress is
Calculation:
Calculate the cross-sectional area of specimen.
Here, diameter of the specimen is
Substitute
Calculate the ultimate tensile stress.
Substitute
Conclusion:
Thus, the ultimate tensile stress on the metal specimen is
(b)
The elongation of the metal specimen.
Answer to Problem 1.5.1P
Explanation of Solution
Given:
The original gage length is
The change in gage length is
Concept Used:
Write the equation to calculate the elongation.
Here, the elongation is
Calculation:
Calculate the elongation of the metal specimen.
Substitute
Conclusion:
Thus, the elongation of the metal specimen is
(c)
The reduction in the cross-sectional area of the metal specimen.
Answer to Problem 1.5.1P
Explanation of Solution
Given:
The original diameter of metal specimen is
The diameter after fracture load is
Concept Used:
Write the equation to calculate reduction in cross-sectional area.
Here, the reduction in cross-sectional area is
Calculation:
Calculate the cross-sectional area after fracture load.
Substitute
Calculate the reduction in the cross-sectional area.
Substitute
Conclusion:
Thus, the reduction in the cross-sectional area is
Want to see more full solutions like this?
Chapter 1 Solutions
STEEL DESIGN (LOOSELEAF)
- A tensile test was performed on a metal specimen having a circular cross section with a diameter of 1 2 inch. The gage length (the length over which the elongation is measured) is 2 inches. For a load 13.5 kips, the elongation was 4.6610 3 inches. If the load is assumed to be within the linear elastic rang: of the material, determine the modulus of elasticity.arrow_forwardThe results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.arrow_forwardA tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.arrow_forward
- In a simple tensile test using a cylindrical test specimen (Dia.=10mm), the applied force was 120 kN and the extension was 2%. Find the modulus of elasticity of that specimen. If the standard modulus of elasticity is 200 GPa, is this material accepted or not? and why?arrow_forwardA tensile test was performed on a metal specimen with a diameter of 1⁄2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The data were plotted on a load-displacement graph, P vs. ∆L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P y∆L 5 1392 kips yin. What is the modulus of elasticity?arrow_forwardTo stretch a 200 mm long tensile test specimen (a) of steel elastically by 0.08 mm. How many loads do I need to apply? (b) What is the maximum length of this sample without plastic deformation? How long can it be extended? (The modulus of elasticity of steel is 210 GPa, yield strength 580 MPa, tensile strength 920 MPa specified as.arrow_forward
- A metal specimen with a square cross-sectional area having a gauge length of 50.0 mm is pulled in tension.If its width at the point of fracture is 5 mm and fractured gauge length is 75 mm. Calculate the ductility interms of:a) percent elongation b) percent reduction in area (Assume that its original width is 9 mm.)arrow_forwarda. Assuming the computer and the printer are turned on, what will be the next step to do when trying to perform a test?b. What part of the UTM will you use to remove the tensile test specimen from the grips?c. In what direction does the lower crosshead move during a tensile test?d. In what direction does the lower crosshead move during a compression test?e. In what direction does the lower crosshead move during a bending test?arrow_forwardThe data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross-section of 0.2 in.^2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches.arrow_forward
- A three-point bending test was performed on an aluminum oxide specimen having a circular cross section of radius 6.7 mm; the specimen fractured at a load of 3190 N when the distance between support points was 46 mm. Another test is to be performed on a specimen of this same material, but one that has a square cross section of 16 mm in length on each edge. At what load would you expect this specimen to fracture if the support point separation is maintained at 46 mm? Ff = ____________ Narrow_forwardA cylindrical metal specimen having an original diameter of 11.26 mm and gauge length of 53.3 mm is pulled in tension until fracture occurs. The diameter at the point of fracture is 6.99 mm, and the fractured gauge length is 66.2 mm. Calculate the ductility in terms of (a) percent reduction in area (percent RA), and (b) percent elongation (percent EL).arrow_forwardA tension test is being conducted on a steel-rod specimen with a gauge length of L0=2 in and initial diameter of d0=0.5 in. Data were collected to form the conventional stress-strain diagram as shown. From the diagram, f = 74.0 ksi, e = 104.0 ksi , g = 85.0 ksi , and h = 0.15 in/in. Assuming that the strain remains constant throughout the region between the gauge points, determine the nominal strain ε experienced by the rod if it is elongated to L = 2.7 in . Assuming that the stress is constant over the cross-sectional area and if the tension force used is P = 11.0 kips, find the nominal stress experienced by the rod. Determine the force P needed to reach the ultimate stress in the steel-rod specimen.arrow_forward
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage LearningMaterials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning