Chapter 1, Problem 1.96ASP

(a)

Interpretation Introduction

Interpretation:

The amount of calories contained in a donut has to be converted into calories and joules.

Concept introduction:

• The conversional formula for Calories (kcal) into calories is,

$\text{1}\text{kcal}\text{=}{\text{10}}^{\text{3}}\text{calories}$

• The conversional formula for Calories (kcal) into joules is,

$\text{1}\text{kcal}\text{=}\text{4184}\text{joules}$

(b)

Interpretation Introduction

Interpretation:

The increasing in temperature of $\text{35}\text{.5}\text{kg}$ water by the energy of one donut has to be calculated.

Concept introduction:

Specific heat capacity: The amount of heat needed to raise the temperature of (1 gm) of a substance by $(1°C)$ is called the specific heat of the substance, it is measured in unites of $cal/(g.°C)$

$Specificheat=\frac{Calories}{grams\times {}^{°}C}$

The specific heat of water is $\text{1}\left(\frac{\text{cal}}{\text{g}\text{.°C}}\right)$.

The relationship between amount of heat and the raising temperature of substances is,

$Heat(cal)=Mass(g)\times TempertureChange(\Delta °C)\times Specificheat\left(\frac{cal}{g.°C}\right)$