Chapter 1, Problem 28CRP

a.

Explanation of Solution

Convert excess $16$ representation $10001$ to its equivalent base ten forms:

• To find the conversion of excess $16$ representation $10001$ to its equivalent base ten form, multiply value of each digit by the quantity associated with its position and add the result:

$\begin{array}{c}1\times 2^4+0\times 2^3+0\times 2^2+0\times 2^1+1\times 2^0\end{array}$

b.

Explanation of Solution

Convert excess $16$ representation $10101$ to its equivalent base ten forms:

• To find the conversion of excess $16$ representation $10101$ to its equivalent base ten form, multiply value of each digit by the quantity associated with its position and add the result:

$\begin{array}{c}1\times 2^4+0\times 2^3+1\times 2^2+0\times 2^1+1\times 2^0\end{array}$

c.

Explanation of Solution

Convert excess $16$ representation $01101$ to its equivalent base ten forms:

• To find the conversion of excess $16$ representation $01101$ to its equivalent base ten form, multiply value of each digit by the quantity associated with its position and add the result:

$\begin{array}{c}0\times 2^4+1\times 2^3+1\times 2^2+0\times 2^1+1\times 2^0=0\end{array}$

d.

Explanation of Solution

Convert excess $16$ representation $01111$ to its equivalent base ten forms:

• To find the conversion of excess $16$ representation $01111$ to its equivalent base ten form, multiply value of each digit by the quantity associated with its position and add the result:

$\begin{array}{c}0\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=0\end{array}$

e.

Explanation of Solution

Convert excess $16$ representation $11111$ to its equivalent base ten forms:

• To find the conversion of excess $16$ representation $11111$ to its equivalent base ten form, multiply value of each digit by the quantity associated with its position and add the result:

$\begin{array}{c}1\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=\mathrm{}\end{array}$