Chapter 1, Problem 45PP

(a)

Interpretation Introduction

Interpretation:

To classify the bond present in the given molecules as covalent, polar covalent or ionic.

Concept introduction:

The bonds present in the atoms may be either covalent, ionic and coordination.  All these is been decided by the electronegativity difference present in the atoms that share the bonds.  If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic.  If the difference is between 0.5 and 1.7 means the bond is polar covalent.  If the difference is lesser than 0.5 means the bond is said to be covalent.  The electronegativity value for the atoms is

Sodium = 0.9

Bromine = 2.8

Oxygen = 3.5

Hydrogen = 2.1

Carbon = 2.5

To Classify the bonds present in the given compounds.

(b)

Interpretation Introduction

Interpretation:

To classify the bond present in the given molecules as covalent, polar covalent or ionic.

Concept introduction:

The bonds present in the atoms may be either covalent, ionic and coordination.  All these is been decided by the electronegativity difference present in the atoms that share the bonds.  If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic.  If the difference is between 0.5 and 1.7 means the bond is polar covalent.  If the difference is lesser than 0.5 means the bond is said to be covalent.  The electronegativity value for the atoms is

Sodium = 0.9

Bromine = 2.8

Oxygen = 3.5

Hydrogen = 2.1

Carbon = 2.5

To Classify: The bonds present in the given compound

(c)

Interpretation Introduction

Interpretation:

To classify the bond present in the given molecules as covalent, polar covalent or ionic.

Concept introduction:

The bonds present in the atoms may be either covalent, ionic and coordination.  All these is been decided by the electronegativity difference present in the atoms that share the bonds.  If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic.  If the difference is between 0.5 and 1.7 means the bond is polar covalent.  If the difference is lesser than 0.5 means the bond is said to be covalent.  The electronegativity value for the atoms is

Sodium = 0.9

Bromine = 2.8

Oxygen = 3.5

Hydrogen = 2.1

Carbon = 2.5

To Classify: The bonds present in the given compounds

(d)

Interpretation Introduction

Interpretation:

To classify the bond present in the given molecules as covalent, polar covalent or ionic.

Concept introduction:

The bonds present in the atoms may be either covalent, ionic and coordination.  All these is been decided by the electronegativity difference present in the atoms that share the bonds.  If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic.  If the difference is between 0.5 and 1.7 means the bond is polar covalent.  If the difference is lesser than 0.5 means the bond is said to be covalent.  The electronegativity value for the atoms is

Sodium = 0.9

Bromine = 2.8

Oxygen = 3.5

Hydrogen = 2.1

Carbon = 2.5

To Classify: The bonds present in the given compounds.

(e)

Interpretation Introduction

Interpretation:

To classify the bond present in the given molecules as covalent, polar covalent or ionic.

Concept introduction:

The bonds present in the atoms may be either covalent, ionic and coordination.  All these is been decided by the electronegativity difference present in the atoms that share the bonds.  If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic.  If the difference is between 0.5 and 1.7 means the bond is polar covalent.  If the difference is lesser than 0.5 means the bond is said to be covalent.  The electronegativity value for the atoms is

Sodium = 0.9

Bromine = 2.8

Oxygen = 3.5

Hydrogen = 2.1

Carbon = 2.5

To find: To classify the bonds present in the given compound