Laboratory Manual Chemistry in Context
Laboratory Manual Chemistry in Context
8th Edition
ISBN: 9780073518121
Author: American Chemical Society
Publisher: McGraw-Hill Education
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Question
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Chapter 1, Problem 6Q

(a)

Interpretation Introduction

Interpretation:

The given amount in percentage has to be expressed in ppm.

Concept Introduction:

    1%=1/1001ppm=1/10000001ppm=0.0001%

(a)

Expert Solution
Check Mark

Explanation of Solution

Given concentration is 0.9%.

Therefore,

    0.9 parts per hundred×106parts permillion100parts per hundred=9ppm

(b)

Interpretation Introduction

Interpretation:

The given amount in ppm has to be expressed in percentage.

Concept Introduction:

    1%=1/1001ppm=1/10000001ppm=0.0001%

(b)

Expert Solution
Check Mark

Explanation of Solution

Given concentration range for the air exhaled from the lungs of a smoker is 20-50 ppm.

Therefore,

    20 ppm×100parts per hundred106ppm=0.002%50ppm×100parts per hundred106ppm=0.0050%

Given concentration range for the air exhaled from the lungs of nonsmokers is 0-2 ppm.

Therefore,

    2 ppm×100parts per hundred106ppm=0.0002%

(c)

Interpretation Introduction

Interpretation:

The given amount in ppm has to be expressed in percentage.

Concept Introduction:

    1%=1/1001ppm=1/10000001ppm=0.0001%

(c)

Expert Solution
Check Mark

Explanation of Solution

Given concentration is 50000 ppm.

Therefore,

    50000 ppm×100parts per hundred106ppm=5%

(d)

Interpretation Introduction

Interpretation:

The given amount in ppm has to be expressed in percentage.

Concept Introduction:

    1%=1/1001ppm=1/10000001ppm=0.0001%

(d)

Expert Solution
Check Mark

Explanation of Solution

Given concentration is 10 ppm.

Therefore,

    10 ppm×100parts per hundred106ppm=0.001%

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Chapter 1 Solutions

Laboratory Manual Chemistry in Context

Ch. 1.12 - Summarize what you have learned about ozone...Ch. 1.13 - Prob. 1.27YTCh. 1.13 - Prob. 1.28YTCh. 1.13 - Prob. 1.29SCCh. 1.13 - Prob. 1.30YTCh. 1.13 - Prob. 1.35CTCh. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Identify three sources of particulate matter found...Ch. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - In these diagrams, two different types of atoms...Ch. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10QCh. 1 - Prob. 11QCh. 1 - Prob. 12QCh. 1 - Prob. 13QCh. 1 - Consider the following blank periodic table. a....Ch. 1 - Classify each of these substances as an element, a...Ch. 1 - Prob. 16QCh. 1 - Hydrocarbons are important fuels that we burn...Ch. 1 - Prob. 18QCh. 1 - Arrange these types of radiation in order of...Ch. 1 - These questions relate to the combustion of...Ch. 1 - Balance these equations in which ethane (C2 H4)...Ch. 1 - Prob. 22QCh. 1 - Count the atoms on both sides of the equation to...Ch. 1 - Prob. 24QCh. 1 - Nail polish remover containing acetone was spilled...Ch. 1 - Prob. 26QCh. 1 - Prob. 27QCh. 1 - Prob. 28QCh. 1 - Prob. 29QCh. 1 - Prob. 30QCh. 1 - A headline from the Anchorage Daily News in Alaska...Ch. 1 - Prob. 32QCh. 1 - Consider how life on Earth would change if the...Ch. 1 - Prob. 34QCh. 1 - Prob. 35QCh. 1 - Prob. 36QCh. 1 - Prob. 37QCh. 1 - Prob. 38QCh. 1 - Prob. 39QCh. 1 - Prob. 40QCh. 1 - Prob. 41QCh. 1 - Prob. 42QCh. 1 - Prob. 43QCh. 1 - Prob. 44QCh. 1 - Prob. 45QCh. 1 - Prob. 46QCh. 1 - Prob. 47QCh. 1 - Prob. 48QCh. 1 - Prob. 49QCh. 1 - Mercury, another serious air pollutant, is not...Ch. 1 - The EPA oversees the Presidential Green Chemistry...Ch. 1 - Prob. 52QCh. 1 - Here are two scanning electron micrograph images...Ch. 1 - Prob. 54QCh. 1 - Prob. 55QCh. 1 - Prob. 56QCh. 1 - Prob. 57QCh. 1 - You may have admired the beauty of hardwood...Ch. 1 - Prob. 59Q
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