21st Century Astronomy (sixth Edition)
6th Edition
ISBN: 9780393675504
Author: Laura Kay, Stacy Palen, George Blumenthal
Publisher: W. W. Norton & Company
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Question
Chapter 1, Problem 9QP
To determine
The increase in the number of viruses in four time step.
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Check out a sample textbook solutionStudents have asked these similar questions
1) An ant population grows at a daily rate of 3/10 times the current popu-
lation. It is known that a constant rate of 36 ants die each day and that
the initial number of ants is 400. How long will it take for all ants to
die? Solve using 1st order differential equations.
A certain strain of bacteria will divide itself from 1 to 2 every to [minute].
As a result, its population can be modeled as
N (t) = No2. ---(eq 1)
N(t) is the population at time t, NO is the population at the beginning = 100, t = time you wait [minute].
You prepare 6 dishes. Each dish contains 100 living bacteria at the beginning.
Then you wait for 20 mins, freeze the first dish to stop the bacteria in the dish from growing.
Then wait for another 20 mins, freeze the second dish (i.e. the total growth time for the second dish is 40 min). Proceed to the next dish in the similar process until
all 6 dishes are done.
After counting all the dish, you collect the data between time and population as follow:
t(min)
N(t)
20
132
220
40
60
311
80
369
100
622
120
836
Find to (the time for bacteria to divide itself). Answer in [min]
Note: if you apply log function on both sides of eq 1 you get
In (N (t)) =t. n2
+ In(No).
---(eq 2)
The water is safe to drink if the number of cells falls below 10 cells/mL. It is 8 a.m. and you have 100,000 cells/mL with D being 15 minutes. You add the bleach to the tank. At what time can you release the water?
Log Nt = Log N0 – t/D. D is the time required for a log kill.
Chapter 1 Solutions
21st Century Astronomy (sixth Edition)
Ch. 1.1 - Prob. 1.1CYUCh. 1.2 - Prob. 1.2CYUCh. 1.3 - Prob. 1.3CYUCh. 1 - Prob. 1QPCh. 1 - Prob. 2QPCh. 1 - Prob. 3QPCh. 1 - Prob. 4QPCh. 1 - Prob. 5QPCh. 1 - Prob. 6QPCh. 1 - Prob. 7QP
Ch. 1 - Prob. 8QPCh. 1 - Prob. 9QPCh. 1 - Prob. 10QPCh. 1 - Prob. 11QPCh. 1 - Prob. 12QPCh. 1 - Prob. 13QPCh. 1 - Prob. 14QPCh. 1 - Prob. 15QPCh. 1 - Prob. 16QPCh. 1 - Prob. 17QPCh. 1 - Prob. 18QPCh. 1 - Prob. 19QPCh. 1 - Prob. 20QPCh. 1 - Prob. 21QPCh. 1 - Prob. 22QPCh. 1 - Prob. 23QPCh. 1 - Prob. 24QPCh. 1 - Prob. 25QPCh. 1 - Prob. 26QPCh. 1 - Prob. 27QPCh. 1 - Prob. 28QPCh. 1 - Prob. 29QPCh. 1 - Prob. 30QPCh. 1 - Prob. 31QPCh. 1 - Prob. 32QPCh. 1 - Prob. 33QPCh. 1 - Prob. 34QPCh. 1 - Prob. 35QPCh. 1 - Prob. 36QPCh. 1 - Prob. 37QPCh. 1 - Prob. 38QPCh. 1 - Prob. 39QPCh. 1 - Prob. 40QPCh. 1 - Prob. 41QPCh. 1 - Prob. 42QPCh. 1 - Prob. 43QPCh. 1 - Prob. 44QPCh. 1 - Prob. 45QP
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