Quantitative Chemical Analysis
Quantitative Chemical Analysis
9th Edition
ISBN: 9781319117313
Author: Harris
Publisher: MAC HIGHER
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Chapter 10, Problem 10.11P

(a)

Interpretation Introduction

Interpretation:

The expressions for KH, Ka1 and Ka2 combined and then find an expression for [CO32-] in terms of   PCO2and[H+] has to be derived.

(a)

Expert Solution
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Explanation of Solution

The expressions for KH, Ka1 and Ka2 as derive as

equationC,[CO32-]=Ka2[HCO3-][H+](F)equationB,[HCO3-]=Ka1[CO2(aq)][H+](G)[HCO3-]valueissubstitutedequationGintoequationH[CO32-]=Ka2Ka1[CO2(aq)][H+]2(H)

[CO32-]=Ka2Ka1PCO2[H+]2(I)

(b)

Interpretation Introduction

Interpretation:

The given conditions is possibly be reached around the year 2100 has to predicted.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given,

PCO2=800μbar,pH=7.8,0oCwefind

[CO32-]=Ka2Ka1KHPCO2[H+]2

10-9.3762molkg-110-6.1004molkg-110-1.2073molkg-1bar-1(800×10-6bar)[10-7.8molkg-1]2=6.6×10-5molkg-1

PCO2=800μbar,pH=7.8,30oCwefind

[CO32-]=Ka2Ka1KHPCO2[H+]2

10-8.8324molkg-110-5.8008molkg-110-1.6048molkg-1bar-1(800×10-6bar)[10-7.8molkg-1]2=1.8×10-4molkg-1

(c)

Interpretation Introduction

Interpretation:

The aragonite and calcite dissolve under the condition has to be predicted.

(c)

Expert Solution
Check Mark

Explanation of Solution

Equilibrium expressions for aragonite and calcite are

CaCO3(s,aragonite)Ca2++CO32-(D)

Ksparg=[Ca2+][CO32-]=10-6.1113mol2kg-2at0oC=10-6.1113mol2kg-2at30oC

CaCO3(s,calcite)Ca2++CO32-(E)

Ksparg=[Ca2+][CO32-]=10-6.3652mol2kg-2at0oC=10-6.3713mol2kg-2at30oC

Reaction quotient at 0oC

[Ca2+][CO32-]=[0.010molkg-1][6.6×10-5molkg-1]=6.6×10-7mol2kg-2=10-6.18mol2kg-2<10-6.1113mol2kg-2aragoniteisdissolve

Reaction quotient at 30oC is

[Ca2+][CO32-]=[0.010molkg-1][1.84×10-4molkg-1]=1.84×10-6mol2kg-2=10-5.74mol2kg-2>10-6.1113mol2kg-2hence neither aragonitenorcalcite

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