Concept explainers
A particle on a ring has a wavefunction
(a) Normalize the wavefunction, where
(b) What is the probability that the particle is in the ring indicated by the angular range
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Chapter 10 Solutions
Bundle: Physical Chemistry, 2nd + Student Solutions Manual
- Consider burning ethane gas, C2H6 in oxygen (combustion) forming CO2 and water. (a) How much energy (in J) is produced in the combustion of one molecule of ethane? (b) What is the energy of a photon of ultraviolet light with a wavelength of 12.6 nm? (c) Compare your answers for (a) and (b).arrow_forwardShow that the value of the Rydberg constant per photon, 2.179 1018 J, is equivalent to 1312 kJ/mol photons.arrow_forwardA normalized wavefunction for a particle confined between 0 and L in the x direction is ψ = (2/L)1/2 sin(πx/L). Suppose that L = 10.0 nm. Calculate the probability that the particle is (a) between x = 4.95 nm and 5.05 nm, (b) between x = 1.95 nm and 2.05 nm, (c) between x = 9.90 nm and 10.00 nm, (d) between x = 5.00 nm and 10.00 nm.arrow_forward
- Imagine a particle free to move in the x direction. Which of the following wavefunctions would be acceptable for such a particle? In each case, give your reasons for accepting or rejecting each function. (1) Þ(x) = x²; (iv) y(x) = x 5. (ii) ¥(x) = ; (v) (x) = e-* ; (iii) µ(x) = e-x²; (vi) p(x) = sinxarrow_forwardP7D.8* A particle is confined to move in a one-dimensional box of length L. If the particle is behaving classically, then it simply bounces back and forth in the box, moving with a constant speed. (a) Explain why the probability density, P(x), for the classical particle is 1/L. (Hint: What is the total probability of finding the particle in the box?) (b) Explain why the average value of x" is (x")= , P(x)x"dx . (c) By evaluating such an integral, find (x) and (x*). (d) For a quantum particle (x)=L/2 and (x*)=L (}-1/2n°n²). Compare these expressions with those you have obtained in (c), recalling that the correspondence principle states that, for very large values of the quantum numbers, the predictions of quantum mechanics approach those of classical mechanics.arrow_forwardThe normalized wave function for a particle in a one- dimensional box in which the potential energy is zero is (x) = /2/L sin (nTx/L), where L is the length of the box (with the left wall at x = 0). What is the probability that the particle will lie between x = 0 and x = ticle is in its n = 2 state? L/4 if the par-arrow_forward
- (a) What is the lowest possible value of the principal quantum number (n) when the angular momentum quantum number (ℓ) is 1? (b) What are the possible values of the angular momentum quantum number (ℓ) when the principal quantum number (n) is 4 and the magnetic quantum number (mℓ) is 0?arrow_forward(a) For a particle in the stationary state n of a one dimensional box of length a, find the probability that the particle is in the region 0xa/4.(b) Calculate this probability for n=1,2, and 3.arrow_forwardFor the system described in Exercise E7B.1(a) (A possible wavefunction for an electron in a region of length L (i.e. from x = 0 to x = L) is sin(2πx/L). Normalize this wavefunction (to 1)), what is the probability of finding the electron between x = L/4 and x = L/2?arrow_forward
- Consider the wave function V222(x, ỹ, z) for a particle in a cubic box. Figure 4.45a shows a contour plot in a cut plane at ž = 0.75. (a) Convince yourself that the contour plot in a cut at ž = 0.25 would have the same pattern, but each positive peak would become negative, and vice versa. (b) Describe the shape of this wave function in a plane cut at ỹ = 0.5.arrow_forwardConsider a 1D particle in a box confined between a = 0 and x = 3. The Hamiltonian for the particle inside the box is simply given by Ĥ . Consider the following normalized wavefunction 2m dz² ¥(2) = 35 (x³ – 9x). Find the expectation value for the energy of the particle inside the box. Give your 5832 final answer for the expectation value in units of (NOTE: h, not hbar!). In your work, compare the expectation value to the lowest energy state of the 1D particle in a box and comment on how the expectation value you calculated for the wavefunction ¥(x) is an example of the variational principle.arrow_forwardThe ground state wave function for a particle in a one-dimensional box is of length L is y = (2/L)¹² sin(7x/L). Calculate the probability of the particle between x=4.00 nm to x = 4.80 nm. Assume the length of the box is 8.5 nm. Answer Choices: (A) 0.840 (B) 0.143 (C) 0.186 (D) 0.256arrow_forward
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