Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
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Textbook Question
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Chapter 10, Problem 111A

Complete Table 10.3.

Chapter 10, Problem 111A, Complete Table 10.3.

(a)
Expert Solution
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Interpretation Introduction

Interpretation: The mass and number of particles in 3.65 moles of magnesium needs to be determined.

Concept Introduction: The mole concept provides the relation between moles, mass and molar mass. The mathematical expression of mole concept can be written as:

  Mole =MassMolar mass

1 mole of any substance contains 6.022 × 1023 number of particles or atoms or molecules.

Answer to Problem 111A

22.0× 1023atoms and 87.6 g

Explanation of Solution

Moles given = 3.65 moles

Molar mass of Mg = 24.0 g/mol

1 mole = 6.022 × 1023 atoms

Calculate number of atoms:

  3.65 moles ×6.022 × 1023atoms1 mole = 22.0× 1023atoms

Calculate mass:

  3.65 moles ×24.0 g1 mole = 87.6 g

(b)
Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The moles and number of particles in 29.54 g of Chromium needs to be determined.

Concept Introduction: The mole concept provides the relation between moles, mass and molar mass. The mathematical expression of mole concept can be written as:

  Mole =MassMolar mass

1 mole of any substance contains 6.022 × 1023 number of particles or atoms or molecules.

Answer to Problem 111A

3.42× 1023atoms and 0.568 moles

Explanation of Solution

Mass of Cr = 29.54 g

Molar mass of Cr = 52.0 g/mol

1 mole = 6.022 × 1023 atoms

Calculate moles:

  29.54 g ×1 mole 52.0  g = 0.568 moles

Calculate number of atoms:

  0.568 moles ×6.022 × 1023atoms1 mole = 3.42× 1023atoms

(c)
Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The mass and number of particles in 0.568 moles of Arsenic needs to be determined.

Concept Introduction: The mole concept provides the relation between moles, mass and molar mass. The mathematical expression of mole concept can be written as:

  Mole =MassMolar mass

1 mole of any substance contains 6.022 × 1023 number of particles or atoms or molecules.

Answer to Problem 111A

 3.42× 1023atoms and 42.5 g

Explanation of Solution

Moles given = 0.568 moles

Molar mass of As= 74.9 g/mol

1 mole = 6.022 × 1023 atoms

Calculate number of atoms:

  0.568 moles ×6.022 × 1023atoms1 mole = 3.42× 1023atoms

Calculate mass:

  0.568 moles ×74.9 g1 mole = 42.5 g

Chapter 10 Solutions

Chemistry: Matter and Change

Ch. 10.1 - Prob. 11SSCCh. 10.1 - Prob. 12SSCCh. 10.1 - Prob. 13SSCCh. 10.1 - Prob. 14SSCCh. 10.2 - Prob. 15PPCh. 10.2 - Prob. 16PPCh. 10.2 - Prob. 17PPCh. 10.2 - Prob. 18PPCh. 10.2 - Prob. 19PPCh. 10.2 - Prob. 20PPCh. 10.2 - Prob. 21PPCh. 10.2 - Prob. 22SSCCh. 10.2 - Prob. 23SSCCh. 10.2 - Prob. 24SSCCh. 10.2 - Prob. 25SSCCh. 10.2 - Prob. 26SSCCh. 10.2 - Prob. 27SSCCh. 10.2 - Prob. 28SSCCh. 10.3 - Prob. 29PPCh. 10.3 - Prob. 30PPCh. 10.3 - Prob. 31PPCh. 10.3 - Prob. 32PPCh. 10.3 - Prob. 33PPCh. 10.3 - Prob. 34PPCh. 10.3 - Prob. 35PPCh. 10.3 - Prob. 36PPCh. 10.3 - Prob. 37PPCh. 10.3 - Prob. 38PPCh. 10.3 - Prob. 39PPCh. 10.3 - Prob. 40PPCh. 10.3 - Prob. 41PPCh. 10.3 - Prob. 42PPCh. 10.3 - Prob. 43PPCh. 10.3 - Prob. 44PPCh. 10.3 - Prob. 45PPCh. 10.3 - Prob. 46PPCh. 10.3 - Prob. 47SSCCh. 10.3 - Prob. 48SSCCh. 10.3 - Prob. 49SSCCh. 10.3 - Prob. 50SSCCh. 10.3 - Prob. 51SSCCh. 10.3 - Prob. 52SSCCh. 10.3 - Prob. 53SSCCh. 10.4 - Prob. 54PPCh. 10.4 - Prob. 55PPCh. 10.4 - Prob. 56PPCh. 10.4 - Prob. 57PPCh. 10.4 - Prob. 58PPCh. 10.4 - Prob. 59PPCh. 10.4 - Prob. 60PPCh. 10.4 - Prob. 61PPCh. 10.4 - Prob. 62PPCh. 10.4 - Prob. 63PPCh. 10.4 - Prob. 64PPCh. 10.4 - Prob. 65PPCh. 10.4 - Prob. 66PPCh. 10.4 - Prob. 67SSCCh. 10.4 - Prob. 68SSCCh. 10.4 - Prob. 69SSCCh. 10.4 - Prob. 70SSCCh. 10.4 - Prob. 71SSCCh. 10.4 - Prob. 72SSCCh. 10.4 - Prob. 73SSCCh. 10.5 - Prob. 74PPCh. 10.5 - Prob. 75PPCh. 10.5 - Prob. 76SSCCh. 10.5 - Prob. 77SSCCh. 10.5 - Prob. 78SSCCh. 10.5 - Prob. 79SSCCh. 10.5 - Prob. 80SSCCh. 10.5 - Prob. 81SSCCh. 10.5 - Prob. 82SSCCh. 10 - Prob. 83ACh. 10 - Prob. 84ACh. 10 - Prob. 85ACh. 10 - Prob. 86ACh. 10 - Prob. 87ACh. 10 - Prob. 88ACh. 10 - Prob. 89ACh. 10 - Determine the number of representative particles...Ch. 10 - Determine the number of representative particles...Ch. 10 - Prob. 92ACh. 10 - Determine the number of moles in each substance....Ch. 10 - Prob. 94ACh. 10 - Prob. 95ACh. 10 - RDA of Selenium The recommended daily allowance...Ch. 10 - Prob. 97ACh. 10 - Prob. 98ACh. 10 - Prob. 99ACh. 10 - Prob. 100ACh. 10 - Prob. 101ACh. 10 - Prob. 102ACh. 10 - Prob. 103ACh. 10 - Prob. 104ACh. 10 - Prob. 105ACh. 10 - Prob. 106ACh. 10 - Prob. 107ACh. 10 - Calculate the mass of each element. a. 5.22 mol of...Ch. 10 - Perform the following conversions. a. 3.50 mol of...Ch. 10 - Determine the mass in grams of each element....Ch. 10 - Complete Table 10.3.Ch. 10 - Convert each to mass in grams. a. 4.221015 atoms c...Ch. 10 - Prob. 113ACh. 10 - Prob. 114ACh. 10 - Prob. 115ACh. 10 - Prob. 116ACh. 10 - Prob. 117ACh. 10 - Prob. 118ACh. 10 - Prob. 119ACh. 10 - Prob. 120ACh. 10 - Prob. 121ACh. 10 - Prob. 122ACh. 10 - Prob. 123ACh. 10 - Prob. 124ACh. 10 - Prob. 125ACh. 10 - Prob. 126ACh. 10 - Prob. 127ACh. 10 - Prob. 128ACh. 10 - Prob. 129ACh. 10 - Prob. 130ACh. 10 - Prob. 131ACh. 10 - Prob. 132ACh. 10 - Prob. 133ACh. 10 - Prob. 134ACh. 10 - Prob. 135ACh. 10 - Prob. 136ACh. 10 - Prob. 137ACh. 10 - Prob. 138ACh. 10 - Prob. 139ACh. 10 - Prob. 140ACh. 10 - Prob. 141ACh. 10 - Prob. 142ACh. 10 - Prob. 143ACh. 10 - Prob. 144ACh. 10 - Prob. 145ACh. 10 - Prob. 146ACh. 10 - Prob. 147ACh. 10 - Pain Relief Acetaminophen, a common aspirin...Ch. 10 - Prob. 149ACh. 10 - Prob. 150ACh. 10 - Prob. 151ACh. 10 - Prob. 152ACh. 10 - Prob. 153ACh. 10 - Prob. 154ACh. 10 - Prob. 155ACh. 10 - Prob. 156ACh. 10 - Prob. 157ACh. 10 - Prob. 158ACh. 10 - Prob. 159ACh. 10 - Prob. 160ACh. 10 - Prob. 161ACh. 10 - Prob. 162ACh. 10 - Express the composition of each compound as the...Ch. 10 - VitaminD3 Your body's ability to absorb calcium is...Ch. 10 - Prob. 165ACh. 10 - Cholesterol Heart disease is linked to high blood...Ch. 10 - Prob. 167ACh. 10 - Prob. 168ACh. 10 - Prob. 169ACh. 10 - Prob. 170ACh. 10 - Prob. 171ACh. 10 - Prob. 172ACh. 10 - Prob. 173ACh. 10 - Prob. 174ACh. 10 - Prob. 175ACh. 10 - Prob. 176ACh. 10 - Prob. 177ACh. 10 - Prob. 178ACh. 10 - Prob. 179ACh. 10 - Determine the mass percent of anhydrous sodium...Ch. 10 - Table 4 shows data from an experiment to determine...Ch. 10 - Chromium(lll) nitrate forms a hydrate that is...Ch. 10 - Determine the percent composition of MgCO35H2O and...Ch. 10 - What is the formula and name of a hydrate that is...Ch. 10 - Gypsum is hydrated calcium sulfate. A 4.89-g...Ch. 10 - A 1.628-g sample of a hydrate of magnesium iodide...Ch. 10 - Borax Hydrated sodiumtetraborate (Na2B4O7xH2O) is...Ch. 10 - Prob. 188ACh. 10 - Prob. 189ACh. 10 - Prob. 190ACh. 10 - Prob. 191ACh. 10 - Prob. 192ACh. 10 - Prob. 193ACh. 10 - Prob. 194ACh. 10 - Prob. 195ACh. 10 - Prob. 196ACh. 10 - Prob. 197ACh. 10 - Prob. 198ACh. 10 - Prob. 199ACh. 10 - Prob. 200ACh. 10 - Prob. 201ACh. 10 - Prob. 202ACh. 10 - Prob. 203ACh. 10 - Prob. 204ACh. 10 - Prob. 205ACh. 10 - Prob. 206ACh. 10 - Prob. 207ACh. 10 - Prob. 208ACh. 10 - Prob. 209ACh. 10 - Prob. 210ACh. 10 - Prob. 211ACh. 10 - Prob. 212ACh. 10 - Prob. 213ACh. 10 - Prob. 214ACh. 10 - Prob. 215ACh. 10 - Prob. 216ACh. 10 - Prob. 1STPCh. 10 - Prob. 2STPCh. 10 - Prob. 3STPCh. 10 - Prob. 4STPCh. 10 - Prob. 5STPCh. 10 - Prob. 6STPCh. 10 - Prob. 7STPCh. 10 - Prob. 8STPCh. 10 - Prob. 9STPCh. 10 - Prob. 10STPCh. 10 - Prob. 11STPCh. 10 - Prob. 12STPCh. 10 - Prob. 13STPCh. 10 - Prob. 14STPCh. 10 - Prob. 15STPCh. 10 - Prob. 16STP
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