Concept explainers
(a)
To find:the centre of the
(a)
Answer to Problem 13STP
The centre of the coordinate
Explanation of Solution
Given:
Concept used:
A perpendicular from the centre to the chord bisects the chord.
In right
Distance or radius cannot be negative.
Calculation:
Consider the following figure:
As centre is equidistance from all the points from the boundary of the circle therefore locate the centre.
Therefore, the centre of the coordinate
(b)
To find:the radius of the circle and use the circle to show the solution.
(b)
Answer to Problem 13STP
The radius of the circle is
Explanation of Solution
Given:
Concept used:
Perimeter of the shape having sides are the sum of all distance of the respective sides.
In right angle triangle Pythagoras theorem can be used as:
Distance or radius cannot be negative.
Calculation:
The radius of the circle is
(c)
To find:the equation of the circle and use the circle to show the solution.
(c)
Answer to Problem 13STP
Explanation of Solution
Given:
Concept used:
Perimeter of the shape having sides are the sum of all distance of the respective sides.
In right angle triangle Pythagoras theorem can be used as:
Distance or radius cannot be negative.
Calculation:
As the centre of the circle is
Hence, the equation of the circle is:
Chapter 10 Solutions
Geometry, Student Edition
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