In the tomato, Solanumesculentum, tall (
Progeny |
Number |
Tall, smooth, round |
|
Dwarf, peach, oblate |
|
Tall, smooth, oblate |
|
Dwarf, peach, round |
|
Tall, peach, oblate |
|
Dwarf, smooth, round |
|
Tall, peach, round |
|
Dwarf, smooth, oblate |
|
|
Want to see the full answer?
Check out a sample textbook solutionChapter 10 Solutions
GENETIC ANALYSIS: INTEGRATED - ACCESS
Additional Science Textbook Solutions
Human Physiology
Essentials of Genetics (9th Edition) - Standalone book
Concepts of Biology
LooseLeaf for Integrated Principles of Zoology
Biology Illinois Edition (Glencoe Science)
- The following corn loci are on one arm of chromosome9 in the order indicated (the distances between themare shown in map units):c-bz-wx-sh-d-centromere12 8 10 20 10C gives colored aleurone; c, white aleurone.Bz gives green leaves; bz, bronze leaves.Wx gives starchy seeds; wx, waxy seeds.Sh gives smooth seeds; sh, shrunken seeds.D gives tall plants; d, dwarf.A plant from a standard stock that is homozygous for allfive recessive alleles is crossed with a wild-type plantfrom Mexico that is homozygous for all five dominantalleles. The F1 plants express all the dominant allelesand, when backcrossed to the recessive parent, give thefollowing progeny phenotypes:colored, green, starchy, smooth, tall 360white, bronze, waxy, shrunk, dwarf 355colored, bronze, waxy, shrunk, dwarf 40white, green, starchy, smooth, tall 46colored, green, starchy, smooth, dwarf 85white, bronze, waxy, shrunk, tall 84colored, bronze, waxy, shrunk, tall 8white, green, starchy, smooth, dwarf 9colored, green, waxy, smooth,…arrow_forwardThe genotype of a Drosophila with a heterozygous translocation between chromosome 2 and chromosome 3 is shown below, where bw = brown eyes and e = ebony body: bw+ bw e Assume there is no crossing over in the female and that alternate = adjacent 1 = adjacent 2 disjunction. [Yes, these assumptions are incorrect, but they make the problem much easier!] Two individuals of the above genotype, i.e. both heterozygous for this 2;3 translocation and both heterozygous for bw (on chromosome 2) and e (on chromosome 3) are crossed. A (Only zygotes with balanced genomes will survive to adulthood. What proportion of F1 zygotes have a balanced genome? B. Draw the genotype(s) and state the phenotype(s) of the surviving progeny you mentioned in part A above. For each different genotype/phenotype indicate it's frequency among the surviving progeny.arrow_forwardIn corn, the genes v (virescent seedlings), pr (red aleurone), and bm (brown midrib) are all on chromosome 5, but not necessarily in the order given. The cross: v+ pr bm/ v pr+ bm+ with v pr bm/ v pr bm produces 1000 progeny with the following phenotypes: v+ pr bm 226 v pr+ bm+ 229 v+ pr bm+ 153 v pr+ bm 185 v+ pr+ bm 59 v pr bm+ 71 v+ pr+ bm+ 36 v pr bm 41 What is the gene order, and the (b) genetic map of these three genes?arrow_forward
- In rice, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of rice plants (i.e. the stamen) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile rice plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Give the result(s) of the cross and explain the phenotype of the offspring.arrow_forwardIn Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up, while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females are mated with true breeding males with curled wings and ebony bodies. Considering Drosophila notation, which of the following correctly diagrams the P1 cross? X X ++ e + + + O+ X + X + ■ + X + + + 3+ X X X X + + Y Y cu cu cu + cu cu J e e e e e (D e + cu cu (Darrow_forwardProgeny of triploid tomato plants often contain parts of an extra chromosome, in addition to the normal complement of 24 chromosomes (J. W. Lesley and M. M. Lesley. 1929. Genetics 14:321–336). Mutants with a part of an extra chromosome are referred to as secondaries. James and Margaret Lesley observed that secondaries arise from triploid (3 n), trisomic (3 n + 1), and double trisomic (3 n + 1 + 1) parents, but never from diploids (2 n). Give one or more possible reasons that secondaries arise from parents that have unpaired chromosomes but not from parents that are normal diploids.arrow_forward
- Male Drosophila from a true-breeding wild-type stock were irradiated with X-rays and then mated with females from a true-breeding stock carrying the following recessive mutations on the X chromosome: yellow body (y), crossveinless wings (cv), cut wings (ct), singed bristles (sn), and miniature wings (m). These markers are known to map in the order: Recessive alleles: y, cv, ct, sn, m Dominant alleles: y+, cv+, ct+, sn+, m+ y-cv-ct-sn-m у CV ct sn m X-rays х х X ct sn CV у m y+ CV+ ct+ sn+ m+ х X ? Exceptional female: Most of the female progeny of this cross were phenotypically wild type, but one female exhibited ct and sn mutant characteristics. When this exceptional ct sn female was mated with a male from the true-breeding wild-type stock, twice as many females as males appeared among the progeny. a. What is the nature of the X-ray-induced mutation present in the exceptional female? b. Draw the X chromosomes present in the exceptional ct sn female as they would appear during pairing…arrow_forwardFemale Drosophila heterozygous for three recessive mutations e (ebony body), st (scarlet eyes), and ss (spineless bristles) were testcrossed, and the following progeny were obtained: Phenotype Number wild-type 67 ebony 8 ebony, scarlet 68 ebony, spineless 347 ebony, scarlet, spineless 78 scarlet 368 scarlet, spineless 10 spineless 54 (a) What indicates that the genes are linked? (b) What was the genotype of the original heterozygous females? (c) What is the order of the genes? (d) What is the map distance between e and st? (e) Between e and ss? (f) What is the coefficient of coincidence? (g) Diagram the crosses in this experiment.arrow_forwardA male Drosophila with wild-type phenotype is discovered to have only seven chromosomes, whereas normally 2n = 8. Close examination reveals that one member of chromosome IV (the smallest chromosome) is attached to (translocated to) the end of chromosome II. If this male mates with a female with a normal chromosome composition who is homozygous for the recessive chromosome IV mutation eyeless (genotype = ee), what would be the eye genotypes, eye phenotypes, and total number of chromosomes in all potential offspring if the male is homozygous for the wild-type allele (EE)? put a table for punnet squarearrow_forward
- Waxy endosperm (wx), virescent seedling (v), and shrunken endosperm (sh) are all recessive mutants in corn. Waxy and shrunken are both on chromosome IX, located 18 map units apart. Virescent is on chromosome V and is not linked to the other loci. A strain of corn that is homozygous for waxy and virescent is crossed to a strain that is homozygous for shrunken endosperm. The F1 were entirely wild type. An F1 individual was then test crossed to a strain that is homozygous for waxy, virescent, and shrunken. Of 1,000 offspring, how many of the offspring will be virescent and shrunken, but not waxy? Using the information from Problem 1, how many of the offspring will be waxy, virescent, and shrunken?arrow_forwardA male Drosophila with wild-type phenotype is discovered to have only seven chromosomes, whereas normally 2n = 8. Close examination reveals that one member of chromosome IV (the smallest chromosome) is attached to (translocated to) the end of chromosome II. If this male mates with a female with a normal chromosome composition who is homozygous for the recessive chromosome IV mutation eyeless (genotype = ee), what would be the eye genotypes, eye phenotypes, and total number of chromosomes in all potential offspring if the male is homozygous for the wild-type allele (EE)?arrow_forwardIn the model plant Arabidopsis thaliana, the following alleles were used in a cross: T = presence of trichomes t = absence of trichomes D = tall plants d = dwarf plants W = waxy cuticle w = nonwaxy A = presence of purple anthocyanin pigment a = absence (white) The T/t and D/d loci are linked 26 m.u. apart on chromosome 1, whereas the W/w and A/a loci are linked 8 m.u. apart on chromosome 2. A pure-breeding double-homozygous recessive trichomeless nonwaxy plant is crossed with another pure-breeding double-homozygous recessive dwarf white plant. a. What will be the appearance of the F1? b. Sketch the chromosomes 1 and 2 of the parents and the F1, showing the arrangement of the alleles.c. If the F1 is testcrossed, what proportion of the progeny will have all four recessive phenotypes?arrow_forward
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education