Concept explainers
A survey of organisms living deep in the ocean revels two new species whose DNA is isolated for analysis. DNA samples from both species are treated to remove nonhistone proteins. Each DNA sample is then treated with DNase I that cuts DNA not protected by histone proteins but is unable to cut DNA bound by histone proteins. Following DNase I treatment, DNA samples are subjected to gel electrophoresis, and the gels are stained to visualize all DNA bands in a gel. The staining patterns of DNA bands from each species are shown in the figure. The number of base pairs in small DNA fragments is shown at the left of the gel. Interpret the gel results in terms of chromatin organization and the spacing of nucleosomes in the chromatin of each species.
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GENETIC ANALYSIS: INTEGRATED - ACCESS
- In one, simple sentence define the function of the following 1. Helicase = 2. Alpha subunit of DNA polymerase III =arrow_forwardYou are interested in studying a gene called pumper that is important for heart function. The pumper gene is only expressed (transcribed) in heart cells, and you think the reason for this may have to do with chromatin structure. To investigate this, you isolate chromatin from heart cells and skin cells, and perform a long digestion of both samples with DNAse I, a non-sequence specific enzyme that will cut the phosphodiester bonds linking adjacent nucleotides. You then remove all proteins and analyze the DNA by gel-electrophoresis. You are able to detect only the DNA fragments that contain the pumper gene. The bands at the top of lane 2 indicate very large DNA fragments that were not able to migrate very far in the gel. The numbers to the left indicate where in the gel DNA fragments of the indicated size would migrate. Based on this data, which of the following is likely to be TRUE regarding the pumper locus in heart cells? (select all that apply) hyper-acetylation of lysine on Histone…arrow_forwardShown below is a drawing showing the result of an experiment in which an RNA molecule is allowed to mix with genomic DNA that has been denatured by boiling, and the two molecules are allowed to hybridize. The DNA strand is presumed to be the lighter-shaded one on the top. Note that only one strand of DNA is shown. This result was the first evidence for which of the following processes? a Replication b Transcription c Translation d Splicingarrow_forward
- Using the figure below identify: What is the role of histones and nucleosomes? How the process of chromatin condensation is performed? What is a function of introns and exons? What is a role of mobile DNA elements? What is a meaning of simple-sequence DNA?arrow_forwardThe regulation of replication is essential to genomic stability. Normally, the DNA is replicated just once in every eukaryotic cell cycle (in the S phase). Normal cells produce protein A, which increases in concentration in the S phase. In cells that have a mutated copy of the gene encoding protein A, the protein is not functional, and replication takes place continuously throughout the cell cycle, with the result that cells may have 50 times the normal amount of DNA. Protein B is normally present in G1, but disappears from the cell nucleus during the S phase. In cells with a mutated copy of the gene encoding protein A, the levels of protein B fail to drop in the S phase and, instead, remain high throughout the cell cycle. When the gene for protein B is mutated, noreplication takes place. Propose a mechanism for how protein A and protein B might normally regulate replication so that each cell gets the proper amount of DNA. Explain how mutation of these genes produces the effects just…arrow_forwardWhat is/are the attributes that make nucleotide excision repair (NER) and base excision repair (BER) similar and/or different from each other? Select the correct response: The NER pathway is the only one that can remove DNA lesions in the strand regardless of their size which is followed by attaching the correct strand, then sealed by a DNA ligase. They both use the enzyme DNA glycosylases that recognizes the damaged DNA segments and proceed with repairing the faulty base in the strand. They differ NER only repairs purine bases while BER repairs pyrimidine bases. They both remove the damaged parts of the DNA where the BER pathway corrects only the identified damaged bases which are usually non-bulky lesions. The NER pathway, on the other hand, repairs the damage by removal of bulky DNA adducts which is a short-single stranded DNA segment. They both utilize the enzyme photolyase to reverse the damages created by the faulty section of the DNA. They both remove the damaged parts of the…arrow_forward
- Which of the following is/are true of DNA general recombination? The process involves invasion of a single-stranded DNA with a free 3'-end into a DNA duplex with the same sequence (on one strand) The process involves formation and resolution of a Holliday structure. The process involves use of a restriction endonuclease. The process involves synthesis of DNA by DNA polymerase.arrow_forwardWhat causes the change in the ability of DNA to absorb UV light when it is denatured? options: In denatured DNA, DNA double helix is disrupted, which causes the exposure of the deoxyribose and thus increases their absorbance of UV light In denatured DNA, DNA double helix is disrupted, which causes the exposure of the phosphate groups and thus increases their absorbance of UV light. In denatured DNA, DNA double helix is disrupted, which causes the exposure of the bases and thus increases their absorbance of UV light. all of the above are correctarrow_forwardseveral options can be correct Consider the following segment of DNA, which is part of a linear chromosome: LEFT 5’.…TGACTGACAGTC….3’ 3’.…ACTGACTGTCAG….5’ RIGHT During RNA transcription, this double-strand molecule is separated into two single strands from the right to the left and the RNA polymerase is also moving from the right to the left of the segment. Please select all the peptide sequence(s) that could be produced from the mRNA transcribed from this segment of DNA. (Hint: you need to use the genetic codon table to translate the determined mRNA sequence into peptide. Please be reminded that there are more than one reading frames.) Question 6 options: ...-Asp-Cys-Gln-Ser-... ...-Leu-Thr-Val-... ...-Thr-Val-Ser-... ...-Leu-Ser-Val-... ...-Met-Asp-Cys-Gln-...arrow_forward
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- Biology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning